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IS25LP256D-RHLA3-TR 数据表(PDF) 126 Page - Integrated Silicon Solution, Inc

部件名 IS25LP256D-RHLA3-TR
功能描述  SERIAL FLASH MEMORY WITH 166/133MHZ MULTI I/O SPI & QUAD I/O QPI DTR INTERFACE
PDF  179 Pages
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制造商  ISSI [Integrated Silicon Solution, Inc]
网页  http://www.issi.com
标志 ISSI - Integrated Silicon Solution, Inc

IS25LP256D-RHLA3-TR 数据表(HTML) 126 Page - Integrated Silicon Solution, Inc

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IS25LP256D
IS25WP256D
Integrated Silicon Solution, Inc.- www.issi.com
126
Rev A15
08/05/2024
Figure 8.88 FRDDTR AX Read Sequence (BDh [EXTADD=0], 3-byte address)
IO0
IO1
3-byte Address
...
...
tV
22 20 18
7 5 3 1 7 5 3 1 7 5 3 1
4 Dummy Cycles
23 21 19
...
6 4 2 0 6 4 2 0 6 4 2 0
Data Out
Data Out
Data Out
16 14 12
17 15 13
10
11
SCK
0
1
2
...
6
7
8
9
10
11
12
13
14
15
16
Mode 3
Mode 0
CE #
7 5 3 1
6 4 2 0
0
1
Mode Bits
...
...
Notes:
1.
If the mode bits=AXh (where X is don’t care), it will keep executing the AX read mode (without command). Only
when the mode bits are different from AXh, the device exits the AX read operation.
2. Number of dummy cycles depends on clock speed. Detailed information in Table 6.11 Read Dummy Cycles.
3. Sufficient dummy cycles are required to avoid I/O contention. If the number of dummy cycles and AX bits cycles
are same, then X should be Hi-Z.
Figure 8.89 FRDDTR AX Read Sequence (BDh [EXTADD=1] or BEh, 4-byte address)
4-byte Address
...
30 28 26
31 29 27
24 22 20
25 23 21
18
19
8
9
10
11
12
13
14
15
16
17
18
IO0
IO1
...
tV
7 5 3 1 7 5 3 1 7 5 3 1
4 Dummy Cycles
...
6 4 2 0 6 4 2 0 6 4 2 0
Data Out
Data Out
Data Out
SCK
0
1
2
...
Mode 3
Mode 0
CE #
7 5 3 1
6 4 2 0
0
1
Mode Bits
...
...
Notes:
1.
If the mode bits=AXh (where X is don’t care), it will keep executing the AX read mode (without command). Only
when the mode bits are different from AXh, the device exits the AX read operation.
2. Number of dummy cycles depends on clock speed. Detailed information in Table 6.11 Read Dummy Cycles.
3. Sufficient dummy cycles are required to avoid I/O contention. If the number of dummy cycles and AX bits cycles
are same, then X should be Hi-Z.



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