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AD8232ACPZ-R7 数据表(PDF) 20 Page - Analog Devices |
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AD8232ACPZ-R7 数据表(HTML) 20 Page - Analog Devices |
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20 / 29 page ![]() Data Sheet AD8232 Rev. B | Page 19 of 28 AC Leads Off Detection The ac leads off detection mode is useful when using two electrodes only (it does not require the use of a driven electrode). In this case, a conduction path must exist between the two electrodes, which is usually formed by two resistors, as shown in Figure 51. These resistors also provide a path for bias return on each input. Connect each resistor to REFOUT or RLD to maintain the inputs within the common-mode range of the instrumentation amplifier. Figure 51. Circuit Configuration for AC Leads Off Detection The AD8232 detects when an electrode is disconnected by forcing a small 100 kHz current into the input terminals. This current flows through the external resistors from IN+ to IN− and develops a differential voltage across the inputs, which is then synchronously detected and compared to an internal threshold. The recommended value for these external resistors is 10 MΩ. Low resistance values make the differential drop too low to be detected and lower the input impedance of the amplifier. When the electrodes are attached to the subject, the impedance of this path should be less than 3 MΩ to maintain the drop below the comparator’s threshold. As opposed to the dc leads off detection mode, the AD8232 is able to determine only that an electrode has lost its connection, not which one. During such an event, the LOD+ pin goes high. In this mode, the LOD− pin is not used and remains in a logic low state. To use the ac leads off mode, tie the AC/DC pin to the positive supply rail. Note that while REFOUT is at a constant voltage value, using the RLD output as the input bias may be more effective in rejecting common-mode interference. STANDBY OPERATION The AD8232 includes a shutdown pin (SDN) that further enhances the flexibility and ease of use in portable applications where power consumption is critical. A logic level signal can be applied to this pin to switch to shutdown mode, even when the supply is still on. Driving the SDN pin low places the AD8232 in shutdown mode and draws less than 200 nA of supply current, offering considerable power savings. To enter normal operation, drive SDN high; when not using this feature, permanently tie SDN to +VS. During shutdown operation, the AD8232 is not able to maintain the REFOUT voltage, but it does not drain the REFIN voltage, thereby maintaining this additional conduction path from the supply to ground. When emerging from a shutdown condition, the charge stored in the capacitors on the high-pass filters can saturate the instru- mentation amplifier and subsequent stages. The use of the fast restore feature helps reduce the recovery time and, therefore, minimize on time in power sensitive applications. INPUT PROTECTION All terminals of the AD8232 are protected against ESD. In addition, the input structure allows for dc overload conditions that are a diode drop above the positive supply and a diode drop below the negative supply. Voltages beyond a diode drop of the supplies cause the ESD diodes to conduct and enable current to flow through the diode. Therefore, use an external resistor in series with each of the inputs to limit current for voltages beyond the supplies. In either scenario, the AD8232 safely handles a continuous 5 mA current at room temperature. For applications where the AD8232 encounters extreme over- load voltages, such as in cardiac defibrillators, use external series resistors and gas discharge tubes (GDT). Neon lamps are com- monly used as an inexpensive alternative to GDTs. These devices can handle the application of large voltages but do not maintain the voltage below the absolute maximum ratings for the AD8232. A complete solution includes further clamping to either supply using additional resistors and low leakage diode clamps, such as BAV199 or FJH1100. As a safety measure, place a resistor between the input pin and the electrode that is connected to the subject to ensure that the current flow never exceeds 10 µA. Calculate the value of this resistor to be equal to the supply voltage across the AD8232 divided by 10 µA. REFOUT 10MΩ 10MΩ IA 2 3 17 8 +VS |
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