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L6258EX 数据表(PDF) 13 Page - STMicroelectronics |
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L6258EX 数据表(HTML) 13 Page - STMicroelectronics |
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13 / 24 page ![]() 13/24 L6258E so the gain of this block is: where: RL = equivalent resistance of the motor winding RS = sense resistor Because of the inductance of the motor LL, the load has a pole at the frequency : Before analysing the error amplifier block and the sense transconductance block, we have to do this consider- ation : AloopdB = AxdB + BxdB Ax|dB = ACpw|dB + ACload|dB and Bx|dB = ACerr|dB + ACsense|dB this means that Ax|dB is the sum of the power amplifier and load blocks; Ax|dB = (29,5) + (-31.4) = -1.9dB The BODE analysis of the transfer function of Ax is: Figure 8. The Bode plot of the Ax|dB function shows a DC gain of -1.9dB and a pole at 163Hz. It is clear now that (because of the negative gain of the Ax function), Bx function must have an high DC gain in ACload V sense v out ------------------ R S R L R S + --------------------- == ACload dB 20 R S R L R S + --------------------- log ⋅ = Aload dB 20 0.33 12 0.33 + ------------------------ log ⋅ 31.4dB – == Fpole 1 2 π L L R L R S + --------------------- ⋅ --------------------------------- = Fpole 1 6.28 12 10 3 – ⋅ 12 0.33 + ------------------------ ⋅ ----------------------------------------- 163Hz == |
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