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ICS853031 数据表(PDF) 9 Page - Integrated Circuit Systems

部件名 ICS853031
功能描述  LOW SKEW, 1-TO-9 DIFFERENTIAL-TO-2.5V/3.3V LVPECL/ECL FANOUT BUFFER
PDF  19 Pages
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制造商  ICST [Integrated Circuit Systems]
网页  http://www.icst.com
标志 ICST - Integrated Circuit Systems

ICS853031 数据表(HTML) 9 Page - Integrated Circuit Systems

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853031AY
www.icst.com/products/hiperclocks.html
REV. B SEPTEMBER 16, 2004
9
Integrated
Circuit
Systems, Inc.
ICS853031
LOW SKEW, 1-TO-9
DIFFERENTIAL-TO-2.5V/3.3V LVPECL/ECL FANOUT BUFFER
APPLICATION INFORMATION
Figure 2 shows how the differential input can be wired to accept
single ended levels. The reference voltage V_REF ~ V
CC/2 is
generated by the bias resistors R1, R2 and C1.This bias circuit
should be located as close as possible to the input pin. The ratio
The clock layout topology shown below is a typical termina-
tion for LVPECL outputs. The two different layouts mentioned
are recommended only as guidelines.
FOUT and nFOUT are low impedance follower outputs that
generate ECL/LVPECL compatible outputs.Therefore, terminat-
ing resistors (DC current path to ground) or current sources
must be used for functionality. These outputs are designed to
drive 50
Ω transmission lines. Matched impedance techniques
should be used to maximize operating frequency and minimize
signal distortion.
Figures 3A and 3B show two different layouts
which are recommended only as guidelines. Other suitable clock
layouts may exist and it would be recommended that the board
designers simulate to guarantee compatibility across all printed
circuit and clock component process variations.
TERMINATION FOR 3.3V LVPECL OUTPUTS
FIGURE 2. SINGLE ENDED SIGNAL DRIVING DIFFERENTIAL INPUT
V
CC - 2V
50
50
RTT
Z
o = 50Ω
Z
o = 50Ω
FOUT
FIN
RTT =
Z
o
1
((V
OH + VOL) / (VCC – 2)) – 2
3.3V
125
125
84
84
Z
o = 50Ω
Z
o = 50Ω
FOUT
FIN
FIGURE 3B. LVPECL OUTPUT TERMINATION
FIGURE 3A. LVPECL OUTPUT TERMINATION
WIRING THE DIFFERENTIAL INPUT TO ACCEPT SINGLE ENDED LEVELS
of R1 and R2 might need to be adjusted to position the V_REF in
the center of the input voltage swing. For example, if the input
clock swing is only 2.5V and V
CC = 3.3V, V_REF should be 1.25V
and R2/R1 = 0.609.
R2
1K
V
CC
CLK_IN
+
-
R1
1K
C1
0.1uF
V_REF



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