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LT8331 数据表(PDF) 17 Page - Analog Devices |
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LT8331 数据表(HTML) 17 Page - Analog Devices |
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17 / 30 page ![]() LT8365 17 Rev. A For more information www.analog.com APPLICATIONS INFORMATION BOOST CONVERTER: LAYOUT HINTS The high speed operation of the LT8365 demands careful attention to board layout. Careless layout will result in per- formance degradation. Figure 5 shows the recommended component placement for a boost converter. Note the vias under the exposed pad. These should connect to a local ground plane for better thermal performance. SEPIC CONVERTER APPLICATIONS The LT8365 can be configured as a SEPIC (single-ended primary inductance converter), as shown in Figure 6. This topology allows for the input to be higher, equal, or lower than the desired output voltage. The conversion ratio as a function of duty cycle is: VOUT + VD VIN = D 1 − D in continuous conduction mode (CCM). Figure 6. LT8365 Configured in a SEPIC Topology L1 L2 VOUT VIN SW FBX GND EN/UVLO LT8365 VIN VCC INT D1 CIN COUT CDC 8365 F06 Themaximumdutycycle(DMAX)occurswhentheconverter operates at the minimum input voltage: DMAX = VOUT + VD VIN(MIN) + VOUT + VD Conversely, the minimum duty cycle (DMIN) occurs when the converter operates at the maximum input voltage: DMIN = VOUT + VD VIN(MAX) + VOUT + VD Be sure to check that DMAX and DMIN obey: DMAX < 1 – Minimum Off-Time(MAX) • fOSC(MAX) and DMIN > Minimum On-Time(MAX) • fOSC(MAX) where Minimum Off-Time, Minimum On-Time and fOSC are specified in the Electrical Characteristics table. SEPIC Converter: The Maximum Output Current Capability and Inductor Selection As shown in Figure 6, the SEPIC converter contains two inductors:L1andL2.L1andL2canbeindependent,butcan also be wound on the same core, since identical voltages are applied to L1 and L2 throughout the switching cycle. For the SEPIC topology, the current through L1 is the converter input current. Based on the fact that, ideally, the output power is equal to the input power, the maximum average inductor currents of L1 and L2 are: IL1(MAX)(AVG) =IIN(MAX)(AVG) =IO(MAX) • DMAX 1 − DMAX IL2(MAX)(AVG) = IO(MAX) In a SEPIC converter, the switch current is equal to IL1 + IL2 when the power switch is on, therefore, the maximum average switch current is defined as: ISW(MAX)(AVG) = IL1(MAX)(AVG) + IL2(MAX)(AVG) = IO(MAX) • 1 1 − DMAX In a SEPIC converter, no DC path exists between the input and output. This is an advantage over the boost converter for applications requiring the output to be disconnected from the input source when the circuit is in shutdown. SEPIC Converter: Switch Duty Cycle and Frequency For a SEPIC converter operating in CCM, the duty cycle of the main switch can be calculated based on the output voltage (VOUT), the input voltage (VIN) and the diode forward voltage (VD). |
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