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L3380L-50-AF5-R 数据表(PDF) 6 Page - Unisonic Technologies

部件名 L3380L-50-AF5-R
功能描述  PWM STEP UP DC-DC CONTROLLER
PDF  9 Pages
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制造商  UTC [Unisonic Technologies]
网页  http://www.utc-ic.com
标志 UTC - Unisonic Technologies

L3380L-50-AF5-R 数据表(HTML) 6 Page - Unisonic Technologies

  L3380L-50-AF5-R Datasheet HTML 1Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 2Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 3Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 4Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 5Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 6Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 7Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 8Page - Unisonic Technologies L3380L-50-AF5-R Datasheet HTML 9Page - Unisonic Technologies  
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L3380
CMOS IC
UNISONICTECHNOLOGIESCO.,LTD
6 of 9
www.unisonic.com.tw
QW-R502-099,A
APPLICATION CIRCUIT INFORMATION
The following equations show the relation of the basic design parameters.
1. Refer to the application circuit, the increasing inductor current when the switch is turn on is given by the following
equation
11
()
LL ON
IN
S
d
iU T
U
U
LL
f
+
∆=
=
(
IN
U :input voltage ;
S
U :transistor saturation voltage)
The decreasing inductor current when the switch is turn off can derive by the equation below
11
1
()
LL OFF
O
D
IN
d
iU T
U
U
U
LL
f
∆=
= −
+
D
U :diode forward voltage)
according to
0
LL
ii
+−
∆+ ∆
= ,the duty ratio is given by
OD
IN
OD
S
UU
U
d
UU
U
+−
=
+−
2. The average current flowing through the inductor is
1
O
L
I
I
d
=
3. We note that
(1
)
OL
I
dI
=−
then we can write:
(1
)
L
OL
L
I
I
di
i
=−
• ∆
substituting
1
LL OFF
iU T
L
∆=
L
i
for equation above, output current is given by
11
(1
)
OL OFF
I
dU T
ICR L
=−
(
ICR =
L
L
i
I
)
11
1
(1
)
(
)
OD
IN
d
Id
Uo U
U
ICR L
f
=−
+
IO=(1-d )2
ICR Lf
UO+UD –UIN
derive that
L =
(1– d)
2(U
O+UD-UIN)
ICR
IO f
4. The peak current of the inductor is given by
1
2
PKL
L
I
Ii
=+ ∆
1
2
L
PKL
L
L
i
I
II
I
=+
according to
ICR =
L
L
i
I
derive that
1
2
PKL
L
I
IICR I
=+
Then derive the following equation for peak current of inductor
1
(1
)
2
PK
L
I
IICR
=+



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