AD8014

–5–

Typical Performance Characteristics–

FREQUENCY – MHz

12

–15

1

1000

100

10

–12

–9

–6

–3

3

6

9

0

G = +1

VO = 200mV p-p

RF = 1k

RL = 1k

VS = 5V

VS = +5V

15

Figure 1. Frequency Response, G = +1, VS = ±5 V and +5 V

VS = 5V

G = +2

RF = 500

VO = 2V p-p

FREQUENCY – MHz

12

–15

1

1000

100

10

–12

–9

–6

–3

3

6

9

0

RL = 50

RL = 75

Figure 2. Frequency Response, G = +2, VO = 2 V p-p

VS = 5V

G = +2

RF = 1k

RL = 1k

FREQUENCY – MHz

12

–12

10

1000

100

0

–9

–6

–3

3

6

9

VO = 0.5V p-p

VO = 1V p-p

VO = 4V p-p

VO = 2V p-p

Figure 3. Bandwidth vs. Output Voltage Level—

Dual Supply, G = +2

FREQUENCY – MHz

2.0

–7.0

1

1000

100

10

–6.0

–5.0

–4.0

–3.0

–1.0

0

1.0

–2.0

VS = 5V

G = –1

RF = 1k

RL = 1k

VO = 2V

VO = 4V

VO = 0.2V

VO = 0.5V

VO = 1V

Figure 4. Bandwidth vs. Output Level—Gain of –1, Dual

Supply

FREQUENCY – MHz

12

1

1000

100

10

–12

–9

–6

–3

3

6

9

0

VS = +5V

G = +2

RF = 1k

RL = 1k

VO = 1V p-p

VO = 3V p-p

VO = 2V p-p

VO = 0.5V p-p

Figure 5. Bandwidth vs. Output Level—Single Supply,

G = +2

FREQUENCY – MHz

2

1

1000

100

10

–8

–7

–5

–4

–2

0

1

–3

–6

–1

VS = +5V

G = –1

RF = 1k

RL = 1k

VO = 2V p-p

VO = 0.2V p-p

VO = 4V p-p

VO = 0.5V p-p

Figure 6. Bandwidth vs. Output Level—Single Supply,

Gain of –1

Rev. C