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L5980 数据表(PDF) 24 Page - STMicroelectronics

部件名 L5980
功能描述  0.7A step-down switching regulator
PDF  37 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

L5980 数据表(HTML) 24 Page - STMicroelectronics

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Application informations
L5980
24/37
The guidelines for positioning the poles and the zeroes and for calculating the component
values can be summarized as follow:
1.
Choose a value for R1, usually between 1k and 5k, in order to have values of C4 and
C5 not comparable with parasitic capacitance of the board.
2.
Choose a gain (R4/R1) in order to have the required bandwidth (BW), that means:
Equation 22
Where fESR is the ESR zero:
Equation 23
and Vs is the saw-tooth amplitude. The voltage feed forward keeps the ratio Vs/Vin
constant.
3.
Calculate C4 by placing the zero one decade below the output filter double pole:
Equation 24
4.
Then calculate C3 in order to place the second pole at four times the system bandwidth
(BW):
Equation 25
For example with VOUT=1.2V, VIN=12V, IO=0.7A, L=22µH, COUT=220µF, ESR=50mΩ, the
type II compensation network is:
In Figure 15 is shown the module and phase of the open loop gain. The bandwidth is about
35kHz and the phase margin is 49°.
R
4
f
ESR
f
LC
------------
⎝⎠
⎛⎞
2
BW
f
ESR
------------
V
S
V
IN
--------- R
1
⋅⋅
=
f
ESR
1
2
π ESR C
OUT
⋅⋅
--------------------------------------------
=
C
4
10
2
π R
4
f
LC
⋅⋅
-------------------------------
=
C
5
C
4
2
π R
4
C
4
4BW
1
⋅⋅⋅
--------------------------------------------------------------
=
R
1
1.1k
=
R
2
249
=
R
4
12k
=
C
4
47nF
=
C
5
68pF
=
,,
,
,



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