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TS4890IST 数据表(PDF) 34 Page - STMicroelectronics |
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TS4890IST 数据表(HTML) 34 Page - STMicroelectronics |
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34 / 46 page ![]() Application information TS4890 34/46 DocID8396 Rev 7 5.4 Power dissipation and efficiency Hypothesis: • Voltage and current in the load are sinusoidal (Vout and Iout) • Supply voltage is a pure DC source (Vcc) Regarding the load we have: and and Then, the average current delivered by the supply voltage is: The power delivered by the supply voltage is Psupply = Vcc IccAVG (W). Then, the power dissipated by the amplifier is Pdiss = Psupply - Pout (W) and the maximum value is obtained when and its value is Remark: This maximum value is only depending on power supply voltage and load values. The efficiency is the ratio between the output power and the power supply. V OUT V PEAK ωtV () sin = I OUT V OUT R L -------------- A () = P OUT V PEAK 2 2R L ------------------- W () = Icc AVG 2 V PEAK πR L ----------------- A () = Pdiss 22Vcc R L π ---------------------- P OUT P OUT W () – = ∂Pdiss ∂P OUT ------------------- 0 = Pdissmax 2Vcc 2 π 2 R L ----------------- W () = |
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