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L3234 数据表(PDF) 16 Page - STMicroelectronics |
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L3234 数据表(HTML) 16 Page - STMicroelectronics |
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16 / 26 page ![]() Two wire impedance To calculate the impedance presented to the two wire line by the SLIC including the protection re- sistors Rp and defined as ZS let: Vrx =0 Il/50’ = Il/50 (in first approximation) Rp = 50 Ω ZS =ZAC/25 + 2RP ZAC to make ZS = 600 Ω ZAC =25 • (ZS -2RP) ZAC =25 ⋅ (600 - 100) ZAC = 12.5K Ω Two wire to four wire gain (Tx gain) Let Vrx =0 Gtx = Vtx Vl Vtx Vl =2 ⋅ ZAC + RPC ZAC + 50RP Example: Calculate Gtx making RPC =50 ⋅ RP Gtx = 2 ⋅ ZAC + 50 ⋅ RP ZAC + 50 ⋅ RP = 2 As you can see the RPC resistor is providing the compensation of the insertion loss introduced by the two external protection resistors RP. Four wire to two wire gain (Rx gain) Let Eg = 0 Grx = Vl Vrx = 50 ⋅ Zl 25 ⋅ (Zl + 2RP ) + ZAC Example: Calculate Grx making ZAC =25 ⋅ (ZML -2 ⋅ RP) Grx = 50 ⋅ Zl 25 ⋅ (Zl + 2RP − 2RP + ZML) Grx = 2 ⋅ Zl Zl + ZML In particular for ZS =Zl:Grx =1 Hybrid function To calculated the transhybrid loss (Thl) let: Eg = 0 Thl = = VTx VRx = 4 ( ZB ZB + ZA − 50 ⋅ ( 2 ⋅ RP + Zl )− 2RPC 50 ⋅ ( 2 ⋅ RP + Zl )− 2RAC ) Example: Calculating Thl making RS =50 ⋅ RP,ZS =25 ⋅ (ZSlic - 2 ⋅ RP) Thl = 4 ⋅ ( ZB ZB + ZA − Zl Zl + ZML ) In particular if ZA ZB = ZS Zl Thl = 0 From the above relation it is evident that if ZS is equal to the Zl used in Thl test, the two ZA,ZB im- pedances can be two resistor of the same value. AC transmission circuit stability To ensure stability of the feedback loop shown in block diagram form in figure 15 two capacitors are required. Figure 16 includes these capacitors Cc and Ch. AC - DC separation The high pass filter capacitor CAC provides the separation between DC circuits and AC circuits. A CAC value of 100mF will position the low end fre- quency response 3dB break point at 7Hz, fsp = 1 2 π ⋅ 220Ω ⋅ CAC Figure 15: Simplified AC Circuits L3234 - L3235 16/26 |
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