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LS7339 数据表(PDF) 4 Page - LSI Computer Systems |
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LS7339 数据表(HTML) 4 Page - LSI Computer Systems |
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4 / 4 page ![]() P AC MAIN S N LOAD C1 T1 L1 R1 A B R4 C3 D1 5 6 7 8 4 3 2 1 C5 C4 TRIG V DD OFF ON V SS OSC CAP SYNC + LS7339 FIGURE 5. A TYPICAL AUTO SHUT-OFF AC POWER SWITCH G MT2 MT1 Z1 - R5 C7 R8 C6 SEE NOTE 1 SEE NOTE 2 R7 R6 R2 R3 C2 ON OFF S1 - + NOTES: 1. Use Connection A when Neutral is not available. Use Connection B when Neutral is available. 2. Snubber Network C7, R8 may be required for some inductive loads. 3. See Table 2 for Component Functional Description. 7339-012703-4 115VAC 220VAC (1)(3) R1 150 Ω, 1W 360 Ω, 2W (2)(4) R1 82 Ω 82 Ω R2 1.5M Ω 1.5M Ω R3 100k Ω 100k Ω R4 100k Ω 100k Ω R5 100 Ω 100 Ω R6 (5)(6) (5)(6) R7 (5)(6) (5)(6) R8 1.8k Ω, 1W 1.8k Ω, 2W C1 0.15µF, 200V 0.15µF, 400V (1) C2 1.0µF, 200V 0.47µF, 400V (2) C2 0.47µF, 200V 0.22µF, 400V (3) C2 0.33µF, 200V 0.22µF, 400V (4) C2 0.22µF, 200V 0.1µF, 400V (1)(2) C3 100µF 100µF (3)(4) C3 47µF 47µF C4 470pF 470pF C5 0.047µF 0.047µF C6 (6) (6) C7 0.1µF, 200V 0.1µF, 400V Z1 15V, 1/2W 15V, 1/2W D1 1N4148 1N4148 L1 100µH 200µH (7)T1 Q4008L4 Q5004L4 (1) LS7339, Connection A (7) Typical (2) LS7339, Connection B (3) LS7340, Connection A (4) LS7340, Connection B (5) 100k Ω ≤ (R6 + R7) ≤10MΩ (6) (R6 + R7)C6 ≥ 5ms All Resistors 1/4W, all Capacitors 25V FIGURE 6. PRODUCING VERY LONG TIME-OUTS BY PULSE MODULATING THE OSCILLATOR Oscillator Components R2 R1 CD4093 C1 = 0.1µF -V R3 C2 - + 4 3 TRIG VDD VSS OSC 5 6 2 1 8 7 OFF ON CAP SYNC T1 T2 Waveform A LS7339 T1 ≈ R1 C1 T2 ≈ (R1 + R2)C1 D1 T1 Period = T1 + T2 Pulse Duty Cycle = T1/Period -V Waveform B (Pulse Modulator) Inverse of Pulse Duty Cycle = Period/T1 = 1 +T2/T1 = 2 + R2/R1 Waveform A Waveform B +V D2 DESCRIPTION: The Oscillator resistor is normally returned to the negative terminal of the DC Supply. If this resistor is returned to a negative-going pulse instaed, the Oscillator R-C effectively becomes multiplied by the inverse of the Pulse Duty Cycle because the Oscillator R-C can chamge only while the pulse is present. (Pulse Modulation) In Figure 6, The Oscillator R is R3, the Oscillator C is C2 and the Pulse Modulator is Waveform B through isolation diode D2. The Multiplier, M = 2 + R2/R1 (the inverse of the Pulse Duty Cycle). EXAMPLE: R3 = 5.1M Ω, C2 = 1.0uF, Pulse Modulator = Waveform B and desired TD1 = 8 hours = 28,800 seconds. Since TD1 = 255 x M x R3 x C2, M calculates to be 22 for the selected Oscillator Components. With M = 22, R2/R1 = 20. If R2 = 3M Ω, R1 = 150kΩ |
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