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L5983 数据表(PDF) 20 Page - STMicroelectronics |
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L5983 数据表(HTML) 20 Page - STMicroelectronics |
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20 / 37 page ![]() Application information L5983 20/37 Equation 19 4. Calculate C5 by placing the second pole at four times the system bandwidth (BW): Equation 20 5. Set also the first pole at four times the system bandwidth and also the second zero at the output filter double pole: Equation 21 The suggested maximum system bandwidth is equals to the switching frequency divided by 3.5 (FSW/3.5), anyway lower than 100 kHz if the FSW is set higher than 500 kHz. For example with VOUT = 3.3 V, VIN = 12 V, IO = 1.5 A, L = 22 μH, COUT = 22 μF, ESR < 1 m Ω, the type III compensation network is: In Figure 12 is shown the module and phase of the open loop gain. The bandwidth is about 77 kHz and the phase margin is 47°. C 4 1 π R 4 f LC ⋅⋅ --------------------------- = C 5 C 4 2 π R 4 C 4 4BW ⋅ 1 – ⋅⋅⋅ -------------------------------------------------------------- = R 3 R 1 4BW ⋅ f LC ----------------- 1 – --------------------------- = C 3 1 2 π R 3 4BW ⋅⋅ ⋅ ----------------------------------------- = , R 1 4.99k Ω = R 2 1.1k Ω = R 3 120 Ω = R 4 4.99k Ω = C 3 4.7nF = C 4 10nF = C 5 68pF = ,, , , , , |
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