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TS4890 数据表(PDF) 25 Page - STMicroelectronics |
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TS4890 数据表(HTML) 25 Page - STMicroelectronics |
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25 / 32 page ![]() TS4890 25/32 s Power dissipation and efficiency Hypothesis : • Voltage and current in the load are sinusoidal (Vout and Iout) • Supply voltage is a pure DC source (Vcc) Regarding the load we have : and and Then, the average current delivered by the supply voltage is The power delivered by the supply voltage is Psupply = Vcc IccAVG (W) Then, the power dissipated by the amplifier is Pdiss = Psupply - Pout (W) and the maximum value is obtained when and its value is Remark : This maximum value is only depending on power supply voltage and load values. The efficiency is the ratio between the output power and the power supply The maximum theoretical value is reached when Vpeak = Vcc, so s Decoupling of the circuit Two capacitors are needed to bypass properly the TS4890. A power supply bypass capacitor Cs and a bias voltage bypass capacitor Cb. Cs has especially an influence on the THD+N in high frequency (above 7kHz) and indirectly on the power supply disturbances. With 100µF, you can expect similar THD+N performances like shown in the datasheet. If Cs is lower than 100µF, in high frequency increase THD+N and disturbances on the power supply rail are less filtered. To the contrary, if Cs is higher than 100µF, those disturbances on the power supply rail are more filtered. Cb has an influence on THD+N in lower frequency, but its function is critical on the final result of PSRR with input grounded in lower frequency. If Cb is lower than 1µF, THD+N increase in lower frequency (see THD+N vs frequency curves) and the PSRR worsens up If Cb is higher than 1µF, the benefit on THD+N in lower frequency is small but the benefit on PSRR is substantial (see PSRR vs. Cb curves). Note that Cin has a non-negligible effect on PSRR in lower frequency. Lower is its value, higher is the PSRR (see fig. 13). s Pop and Click performance In order to have the best performances with the pop and click circuitry, the formula below must be follow : With and ) V ( t sin V V PEAK OUT ω = ) A ( R V I L OUT OUT = ) W ( R 2 V P L 2 PEAK OUT = ) A ( R V 2 Icc L PEAK AVG π = ) W ( P P R Vcc 2 2 Pdiss OUT OUT L − π = 0 P Pdiss OUT = ∂ ∂ ) W ( R Vcc 2 max Pdiss L 2 2 π = Vcc 4 V ply sup P P PEAK OUT π = = η % 5 . 78 4 = π b in τ ≤ τ ) s ( C ) R R ( in feed in in × + = τ ) s ( C k 50 b b × Ω = τ |
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