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AD8209WBRMZ-R7 数据表(PDF) 13 Page - Analog Devices |
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AD8209WBRMZ-R7 数据表(HTML) 13 Page - Analog Devices |
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13 / 16 page ![]() AD8209 Rev. 0 | Page 13 of 16 Internal Signal Overload Considerations When configuring the gain for values other than 14, the maximum input voltage with respect to the supply voltage and ground must be considered because either the preamplifier or the output buffer reaches its full-scale output (VS − 0.1 V) with large differential input voltages. The input of the AD8209 is limited to (VS − 0.1) ÷ 7 for overall gains of ≤7 because the preamplifier, with its fixed gain of 7 V/V, reaches its full-scale output before the output buffer. For gains greater than 7, the swing at the buffer output reaches its full scale first and then limits the AD8209 input to (VS − 0.1) ÷ G, where G is the overall gain. LOW-PASS FILTERING In many transducer applications, it is necessary to filter the signal to remove spurious high frequency components, including noise, or to extract the mean value of a fluctuating signal with a peak- to-average ratio (PAR) greater than unity. For example, a full-wave rectified sinusoid has a PAR of 1.57, a raised cosine has a PAR of 2, and a half-wave sinusoid has a PAR of 3.14. Signals with large spikes may have PARs of 10 or more. When implementing a filter, the PAR should be considered so that the output of the AD8209 preamplifier (A1) does not clip before A2; otherwise, the nonlinearity would be averaged and appear as an error at the output. To avoid this error, both amplifiers should clip at the same time. This condition is achieved when the PAR is no greater than the gain of the second amplifier (2 for the default configuration). For example, if a PAR of 5 is expected, the gain of A2 should be increased to 5. Low-pass filters can be implemented in several ways by using the features provided by the AD8209. In the simplest case, a single-pole filter (20 dB/decade) is formed when the output of A1 is connected to the input of A2 via the internal 100 kΩ resistor by tying Pin 3 to Pin 4 and adding a capacitor from this node to ground, as shown in Figure 32. If a resistor is added across the capacitor to lower the gain, the corner frequency increases; therefore, gain should be calculated using the parallel sum of the resistor and 100 kΩ. GND NC –IN +IN A1 +VS A2 OUT AD8209 5V VDIFF VCM CF NC = NO CONNECT OUTPUT fC = 1 2 πC105 C IN FARADS + – + – Figure 32. Single-Pole, Low-Pass Filter Using the Internal 100 kΩ Resistor If the gain is raised using a resistor, as shown in Figure 30, the corner frequency is lowered by the same factor as the gain is raised. Therefore, using a resistor of 200 kΩ (for which the gain would be doubled), results in a corner frequency scaled to 0.796 Hz μF (0.039 μF for a 20 Hz corner frequency). GND NC –IN +IN A1 +VS A2 OUT AD8209 5V VDIFF VCM C C NC = NO CONNECT OUTPUT fC(Hz) = 1/C(µF) 255k Ω + – + – Figure 33. Two-Pole, Low-Pass Filter A two-pole filter with a roll-off of 40 dB/decade can be implemented using the connections shown in Figure 33. This configuration is a Sallen-Key form based on a ×2 amplifier. It is useful to remember that a two-pole filter with a corner frequency of f2 and a single-pole filter with a corner frequency of f1 have the same attenuation, that is, 40 log (f2/f1), as shown in Figure 34. Using the standard resistor value shown in Figure 33 and capacitors of equal values, the corner frequency is conveniently scaled to 1 Hz μF (0.05 μF for a 20 Hz corner frequency). A maximal flat response occurs when the resistor is lowered to 196 kΩ, scaling the corner frequency to 1.145 Hz μF. The output offset is raised by approximately 5 mV (equivalent to 250 μV at the input pins). 40log (f2/f1) f1 f2 f22/f1 FREQUENCY A 1-POLE FILTER, CORNER f1, AND A 2-POLE FILTER, CORNER f2, HAVE THE SAME ATTENUATION –40log (f2/f1) AT FREQUENCY f22/f1 20dB/DECADE 40dB/DECADE Figure 34. Comparative Responses of Single-Pole and Two-Pole Low-Pass Filters |
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