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MIC2829 数据表(PDF) 35 Page - Micrel Semiconductor |
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MIC2829 数据表(HTML) 35 Page - Micrel Semiconductor |
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35 / 52 page ![]() Micrel Inc. MIC2829 May 2010 35 M9999-051410-B becomes increasingly critical in efficiency calculations. As the inductors are reduced in size, the DC resistance (DCR) can become quite significant. The DCR losses can be calculated as follows: PL_LOSS ≈ IOUT 2 × DCR From that, the loss in efficiency due to inductor resistance can be calculated as follows: 100 1 _ × ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎣ ⎡ ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + × × − ≈ LOSS L OUT OUT OUT OUT P I V I V Loss Efficiency Efficiency loss due to DCR is minimal at light loads and gains significance as the load is increased. Inductor selection becomes a trade-off between efficiency and size in this case. Partitioning for Optimal System Efficiency Many of the LDOs can be post-regulated from the DC regulator output to increase system efficiency. For example, DC4 output can be used to power low output voltage LNRs in order to reduce power loss during voltage conversion. Thermal Considerations Whenever there is power dissipation, there will be thermal considerations. In order to account for the temperature rise in a PMIC with multiple regulators, the power dissipation in each regulator must be accounted for. The current rating of each regulator is shown below: Output Maximum Load (mA) DC1 1000 DC2 300 DC3 600 DC4 600 DC5 800 DC6 800 LDO1 200 LDO2 200 LDO3 200 LDO4 200 LDO5 200 LDO6 200 LDO7 200 LDO8 200 LDO9 200 LDO10 200 LDO11 200 SIMPWR 50 Table 5. Output Current Rating If each regulator on the MIC2829 is turned on at its maximum load capability, the power dissipation into the device will cause excessive temperature rise. In order to avoid excessive temperature rise and unexpected thermal shutdown the total power dissipation should be considered. LDO Power Dissipation The power dissipation of a LDO can be calculated with the input voltage, the output voltage and the output current, as shown in the following equation. PD_LDO ≈ (VIN – VOUT) IOUT + VIN IGND Since the ground current (IGND) is relatively low, it can be ignored for this calculation. For example, if the input voltage is 3.3V, the output voltage is 2.8V and the output current of the LDO is 200mA, the power dissipation of the LDO can be calculated as follow: PD_LDO ≈ (3.3V – 2.8V) × 200mA PD_LDO ≈ 0.1W Buck Regulator Power Dissipation Neglecting some minor losses, the power dissipation in a MIC2829 buck regulator (DC1 to DC6) is approximately the switcher’s input power minus the switcher’s output power and minus the power loss in the inductor. PD_SWITCHER ≈ PIN x IIN – POUT x IOUT – PL_LOSS Total Power Dissipation The total power dissipation in the MIC2829 package is equal to the sum of the power loss of each regulator. PD_TOTAL ≈ SUM (PD_LDOS + PD_SWITCHERS) The maximum power dissipation of the package can be calculated by the following equation. ⎟⎟ ⎠ ⎞ ⎜⎜ ⎝ ⎛ − ≈ JA A ) J( ) D( θ T T P max max TJ(MAX) is the maximum junction temperature (125°C), TA is the ambient temperature and θ JA is the junction-to- ambient thermal resistance of the package (38.7°C/W). The following table shows the maximum power dissipation versus the ambient temperature. |
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