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SC1406GCTSTR 数据表(PDF) 16 Page - Semtech Corporation |
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SC1406GCTSTR 数据表(HTML) 16 Page - Semtech Corporation |
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16 / 28 page ![]() 16 ã 2000 Semtech Corp. www.semtech.com POWER MANAGEMENT SC1406G Rearranging equation 1), we select the minimum inductor value. G. This value of inductance is required up to maximum load. Inductors with a swinging choke characteristic, where the zero current value of inductance is much less than the full load current inductance can be used, as long as the above restriction is met. A value of 1.5uH is used to allow tolerances. Then, the worst-case (low input voltage) response time (the time for the current to reach the new transient value) is: H. Add ~100ns for the SC1405/06 response. Since the shaded area is triangular, the total charge taken out of the capacitor = (DI ? Dt) / 2. Q = C ? DV = (DI ? Dt) / 2, therefore; I. This condition applies only to the positive transient. For negative load steps, the capacitance also has to be large enough to absorb the energy in the inductance. Since: J. Using Panasonic SP-Caps, the EEFUE0E221R is 220uF at 2.5V with 15mW ESR. Two are sufficient to meet ESR requirements, but three are required to meet the capacitance requirement, when tolerances are considered. The Sanyo POSCAP 4TPC150 is a 150uF capacitor with a maximum ESR specification of 45mW; six are required to meet the ESR requirement. The resulting 900mF exceeds the capacitance requirement. Other Component Selection: As a compromise between current sensing accuracy, efficiency, and availability, a current sense resistor of 3mW is used. The power dissipation is I2xR, or 555mW, so choose a 1W or larger resistor for design margin. The connections to CMP, CMPREF, CL, and CLREF (pins 25 through 28) are two differential pairs connected to the current sense resistor. In order to cancel out common-mode noise, resistor pairs R3-R4 and R5-R6 should be equal. For the time being, assume R3=R4=R5=R6=1kW. These values may be adjusted later if required. The current limit is a function of peak current and should be set at about 125% of the peak to allow for some overshoot of inductor current during transients. For L=1.5uH, and F=300kHz: K. So, set the current limit at approximately 18.5A. Using equation 10): L. M. Using equation 6) we calculate R DAC: N. The offset resistor, R22, is calculated from equation 8): O. Equation 5) is used to calculate R1 by calculating a new value of V HYS which accounts for the IMVP and offset dividers, and then plugging the resulting value into equation 3). P. Q. LMIN dMIN VINMAX VDAC − () ESR MAX RCS + () ⋅ FS VRIPPLE ⋅ ⋅ := LMIN 1.426 10 6 − × H = dT LMIN ICC650MAX ICC650SG − () ⋅ VINMIN VDAC − := dT 1.936 10 6 − × s = CMINP ICC650MAX ICC650SG − () dT 100 10 9 − ⋅ sec ⋅ + () ⋅ 2VIMVP ⋅ := C 1.186 10 4 − × F = CMINN LMIN ICC650MAX 2 ICC650SG 2 − VCC650MAXTRANS 2 VFL 2 − ⋅ := CMINN 4.045 10 4 − × F = IPEAK ICC650MAX VINMAX VDAC − () d MIN ⋅ 2LMIN ⋅ FS ⋅ + := IPEAK 15.327 A = ICLMAX IPEAK 1.25 ⋅ := ICLMAX 19.159A = RCLSET 3VREF ⋅ RCLOH ⋅ RCS ICLMAX ⋅ := RCLSET 8.873 10 4 ×Ω = RDAC VIMVP ICC650MAX RCS ⋅ − () R CORE ⋅ ICC650MAX RCS ⋅ := RDAC 1.397 10 3 ×Ω = ROFF ROH VNL RDAC ⋅ VDAC + VNL VDAC 1 − := ROFF 1.068 10 5 ×Ω = VHYS VRIPPLE RCORE ROFF ⋅ ROH RDAC ⋅ − () ⋅ ESR RCS RCORE ⋅ ROFF ROH + () RCORE ROFF ⋅ RDAC ROH ⋅ − ⋅ + 2 ESR ⋅ RCORE ⋅ ROFF ROH + () ⋅ ⋅ := RHYS 2 VREF ROH ⋅ VHYS ⋅ := V HYS 0.027 V = R HYS 1.281 10 5 ×Ω = |
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