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ADE7759 数据表(PDF) 19 Page - Analog Devices |
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ADE7759 数据表(HTML) 19 Page - Analog Devices |
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19 / 32 page ![]() REV. 0 ADE7759 –19– CHANNEL 2 ADC Channel 2 Sampling In Channel 2 waveform sampling mode (MODE[14:13] = 1, 1 and WSMP = 1) the ADC output code scaling for Channel 2 is the same as Channel 1, i.e., the output swings between D7AE1h (–165,151) and 2851Fh (+165,151)—see ADC Channel 1 section. However, before being passed to the waveform register, the ADC output is passed through a single-pole, low-pass filter with a cutoff frequency of 156 Hz. The plots in Figure 26 show the magnitude and phase response of this filter. FREQUENCY – Hz 0 101 –20 –40 –60 –80 102 103 0 –20 60Hz, –0.6dB 60Hz, –21.04 –10 Figure 26. Magnitude and Phase Response of LPF1 The LPF1 has the effect of attenuating the signal. For example, if the line frequency is 60 Hz, the signal at the output of LPF1 will be attenuated by 7%. Hf Hz Hz dB () . – . = + == 1 1 60 156 093 0 6 2 Note that LPF1 does not affect the power calculation. The signal processing chain in Channel 2 is illustrated in Figure 27. Unlike Channel 1, Channel 2 has only one analog input range (0.5 V differential). However, like Channel 1, Channel 2 does have a PGA with gain selections of 1, 2, 4, 8, and 16. For energy measurement, the output of the ADC is passed directly to the multiplier and is not filtered. An HPF is not required to remove any dc offset since it is only required to remove the offset from one channel to eliminate errors due to offsets in the power calculation. When in waveform sample mode, one of four output sample rates can be chosen by using Bits 11 and 12 of the Mode register. The available output sample rates are 27.9 kSPS, 14 kSPS, 7 kSPS, or 3.5 kSPS— see Mode Register section. The interrupt request output IRQ signals a new sample availability by going active low. The timing is the same as that for Channel 1 and is shown in Figure 24. ADC 2 V1 0V ANALOG INPUT RANGE 0.5V, 0.25V, 0.125V, 62.5mV, 31.25mV REFERENCE 1 20 TO WAVEFORM REGISTER LPF1 –63% TO +63% FS TO MULTIPLIER PGA2 1, 2, 4, 8, 16 {GAIN [7:5]} V2P V2N V2 2.42V 40000h 2851Fh 257F6h 00000h DA80Ah D7AE1h C0000h LPF OUTPUT WORD RANGE +FS +63% FS +59% FS –59% FS –63% FS –FS Figure 27. ADC and Signal Processing in Channel 2 PHASE COMPENSATION When the HPF is disabled, the phase error between Channel 1 and Channel 2 is zero from dc to 3.5 kHz. When HPF1 is enabled, Channel 1 has a phase response illustrated in Figures 29 and 30. Also shown in Figure 31 is the magnitude response of the filter. As can be seen from the plots, the phase response is almost zero from 45 Hz to 1 kHz. This is all that is required in typical energy measurement applications. However, despite being internally phase compensated, the ADE7759 must work with transducers that may have inherent phase errors. For example, a phase error of 0.1 ° to 0.3° is not uncommon for a CT (Current Transformer). These phase errors can vary from part to part, and they must be corrected in order to perform accurate power calculations. The errors associated with phase mismatch are particularly noticeable at low power factors. The ADE7759 provides a means of digitally calibrating these small phase errors. The ADE7759 allows a small time delay or time advance to be introduced into the signal processing chain in order to compensate for small phase errors. Because the compensation is in time, this technique should only be used for small phase errors in the range of 0.1 ° to 0.5°. Correcting large phase errors using a time shift technique can introduce signifi- cant phase errors at higher harmonics. The Phase Calibration register (PHCAL[7:0]) is a two’s comple- ment signed single byte register that has values ranging from 9Eh (–98 in decimal) to 5Ch (92 in decimal). By changing the PHCAL register, the time delay in the Channel 2 signal path can change from –110 µs to +103 µs (CLKIN = 3.579545 MHz). One LSB is equivalent to 1.12 µs time delay or advance. With a line fre- quency of 60 Hz, this gives a phase resolution of 0.024 ° at the fundamental (i.e., 360 °× 1.12 µs × 60 Hz). Figure 28 illustrates how the phase compensation is used to remove a 0.1 ° phase lead in Channel 1 due to the external transducer. In order to cancel the lead (0.1 °) in Channel 1, a phase lead must also be intro- duced into Channel 2. The resolution of the phase adjustment allows the introduction of a phase lead in increments of 0.024 °. The phase lead is achieved by introducing a time advance into Channel 2. A time advance of 4.48 µs is made by writing –4 (FCh) to the time delay block, thus reducing the amount of time delay by 4.48 µs, or equivalently, a phase lead of approximately 0.1° at line frequency of 60 Hz. |
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