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MAT02EH 数据表(PDF) 9 Page - Analog Devices |
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MAT02EH 数据表(HTML) 9 Page - Analog Devices |
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9 / 12 page ![]() MAT02 –9– REV. C approximately 26 mV and the error due to an rBEIC term will be rBEIC/26 mV. Using an rBE of 0.4 Ω for the MAT02 and assum- ing a collector current range of up to 200 µA, then a peak error of 0.3% could be expected for an rBEIC error term when using the MAT02. Total error is dependent on the specific application configuration (multiply, divide, square, etc.) and the required dynamic range. An obvious way to reduce ICrBE error is to re- duce the maximum collector current, but then op amp offsets and leakage currents become a limiting factor at low input lev- els. A design range of no greater than 10 µA to 1 mA is generally recommended for most nonlinear function circuits. A powerful technique for reducing error due to ICrBE is shown in Figure 20. A small voltage equal to ICrBE is applied to the tran- sistor base. For this circuit: VB = RC R2 V1 and ICrBE = rBE R1 V1 (10) The error from rBEIC is cancelled if RC/R2 is made equal to rBE/ R1. Since the MAT02 bulk resistance is approximately 0.39 Ω, an RC of 3.9 Ω and R 2 of 10 R1 will give good error cancellation. In more complex circuits, such as the circuit in Figure 19, it may be inconvenient to apply a compensation voltage to each individual base. A better approach is to sum all compensation to the bases of Q1. The “A” side needs a base voltage of (VO/RO + VZ/R3) rBE and the “B” side needs a base voltage of (VX/R1+VY/ R2) rBE. Linearity of better than ±0.1% is readily achievable with this compensation technique. Operational amplifier offsets are another source of error. In Fig- ure 20, the input offset voltage and input bias current will cause an error in collector current of (VOS/R1) + IB. A low offset op amp, such as the OP07 with less than 75 µV of V OS and IB of less than ±3 nA, is recommended. The OP22/OP32, a program- mable micropower op amp, should be considered if low power consumption or single-supply operation is needed. The value of frequency-compensating capacitor (CO) is dependent on the op amp frequency response and peak collector current. Typical val- ues for CO range from 30 pF to 300 pF. . . . FOUR-QUADRANT MULTIPLIER A simplified schematic for a four-quadrant log/antilog multiplier is shown in Figure 21. As with the previously discussed one- quadrant multiplier, the circuit makes IO = I1 I2/I3. The two input currents, I1 and I2, are each offset in the positive direction. This positive offset is then subtracted out at the output stage. Assuming ideal op amps, the currents are: I1 = V X R1 + V R R2 , I2 = VY R1 + V R R2 (11) IO = V X R1 + VY R1 + V R R2 + VO RO , I3 = V R R2 From IO = I1 I2/I3, the output voltage will be: VO = ROR2 R1 2 V XVY V R (12) Figure 20. Compensation of Bulk Resistance Error Extrinsic resistive terms and the early effect cause departure from the ideal logarithmic relationship. For small VCB, all of these effects can be lumped together as a total effective bulk re- sistance rBE. The rBEIC term causes departure from the desired logarithmic relationship. The rBE term for the MAT02 is less than 0.5 Ω and ∆r BE between the two sides is negligible. Returning to the multiplier/divider circuit of Figure 1 and using Equation (4): VBE1A + VBE2A – VBE2B –VBE1B + (I1 + I2 – IO – I3) rBE = 0 If the transistor pairs are held to the same temperature, then: kT q In I1I2 I3IO = kT q In IS1AIS2A IS1BIS2B + (I1 + I2 – IO – I3) rBE (6) If all the terms on the right-hand side were zero, then we would have In (I1 I2/I3 IO) equal to zero which would lead directly to the desired result: IO = I1I2 I3 , where I1, I2, I3, IO > 0 (7) Note that this relationship is temperature independent. The right-hand side of Equation (6) is near zero and the output cur- rent IO will be approximately I1 I2/I3. To estimate error, define ø as the right-hand side terms of Equation (6): ø = In IS1AIS2A IS1BIS2B + q kT (I1 + I2 – IO – I3) rBE (8) For the MAT02, In (ISA/ISB) and ICrBE are very small. For small ø, εØ ~ 1 + ø and therefore: I1I2 I3IO = 1 + ø (9) IO ~ I1I2 I3 (1 – ø) The In (ISA/ISB) terms in ø cause a fixed gain error of less than ±0.6% from each pair when using the MAT02, and this gain error is easily trimmed out by varying RO. The ICrBE terms are more troublesome because they vary with signal levels and are multiplied by absolute temperature. At 25 °C, kT/q is |
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