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LTC3602 数据表(PDF) 21 Page - Linear Technology

部件名 LTC3602
功能描述  Dual Channel 3A, 20V Monolithic Synchronous Step-Down Regulator
PDF  28 Pages
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制造商  LINER [Linear Technology]
网页  http://www.linear.com
标志 LINER - Linear Technology

LTC3602 数据表(HTML) 21 Page - Linear Technology

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LTC3633A-2/LTC3633A-3
21
3633a23f
Board Layout Considerations
When laying out the printed circuit board, the following
checklist should be used to ensure proper operation of the
LTC3633A-2. Check the following in your layout:
1) Do the input capacitors connect to the PVIN and PGND
pins as close as possible? These capacitors provide
the AC current to the internal power MOSFETs and their
drivers.
2) The output capacitor, COUT, and inductor L should be
closely connected to minimize loss. The (–) plate of
COUT should be closely connected to both PGND and
the (–) plate of CIN.
3) The resistive divider, (e.g. R1 to R4 in Figure 9) must be
connected between the (+) plate of COUT and a ground
line terminated near SGND. The feedback signal VFB
should be routed away from noisy components and
traces, such as the SW line, and its trace length should
be minimized. In addition, the RT resistor and loop com-
pensation components should be terminated to SGND.
4) Keep sensitive components away from the SW pin.
The RT resistor, the compensation components, the
feedback resistors, and the INTVCC bypass capacitor
should all be routed away from the SW trace and the
inductor L.
5) A ground plane is preferred, but if not available, the
signal and power grounds should be segregated with
both connecting to a common, low noise reference point.
The connection to the PGND pin should be made with
a minimal resistance trace from the reference point.
6) Flood all unused areas on all layers with copper in order
to reduce the temperature rise of power components.
These copper areas should be connected to the exposed
backside of the package (PGND).
Refer to Figures 10 and 11 for board layout examples.
Design Example
As a design example, consider using the LTC3633A-2 in
an application with the following specifications: VIN(MAX)=
13.2V, VOUT1 = 1.8V, VOUT2 = 3.3V, IOUT(MAX) = 3A, IOUT(MIN)
= 10mA, f = 2MHz, VDROOP ~ (5% • VOUT). The following
discussion will use equations from the previous sections.
APPLICATIONS INFORMATION
Because efficiency is important at both high and low load
current, Burst Mode operation will be utilized.
First, the correct RT resistor value for 2MHz switching fre-
quency must be chosen. Based on the equation discussed
earlier, RT should be 160k; the closest standard value is
162k. RT can be tied to INTVCC if switching frequency
accuracy is not critical.
Next, determine the channel 1 inductor value for about
40% ripple current at maximum VIN:
L1=
1.8V
2MHz • 1.2A
⎟ 1−
1.8V
13.2V
⎟ = 0.64μH
A standard value of 0.68μH should work well here. Solving
the same equation for channel 2 results in a 1μH inductor.
COUT will be selected based on the charge storage require-
ment. For a VDROOP of 90mV for a 3A load step:
COUT1
3• ΔIOUT
f• VDROOP
=
3• (3A)
(2MHz)(90mV)
= 50μF
A 47μF ceramic capacitor should be sufficient for channel 1.
Solving the same equation for channel 2 (using 5% of
VOUT for VDROOP) results in 27μF of capacitance (22μF is
the closest standard value).
CIN should be sized for a maximum current rating of:
IRMS = 3A
1.8V 13.2V − 1.8V
()
13.2V
= 1A
Solving this equation for channel 2 results in an RMS
input current of 1.3A. Decoupling each PVIN input with
a 47μF ceramic capacitor should be adequate for most
applications.
Lastly, the feedback resistors must be chosen. Picking
R1 and R3 to be 12.1k, R2 and R4 are calculated to be:
R2 = (12.1k) •
1.8V
0.6V
–1
⎟ = 24.2k
R4 = (12.1k) •
3.3V
0.6V
–1
⎟ = 54.5k
The final circuit is shown in Figure 9.



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