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AD8244BRMZ-R7 数据表(PDF) 16 Page - Analog Devices |
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AD8244BRMZ-R7 数据表(HTML) 16 Page - Analog Devices |
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16 / 20 page ![]() AD8244 Data Sheet APPLICATIONS INFORMATION ELECTROCARDIOGRAM (ECG) In an ECG system, mismatches between the source impedance of different leads, working against the input impedance of the front-end amplifier, can create unbalanced resistor dividers that potentially reduce the system CMRR. When presented to a moderately high input impedance amplifier, the combined impedance of the skin, electrolyte, electrodes, and the protection resistors can be enough to cause power line noise pickup, current noise issues, and signal division. Dry electrode systems, which are becoming increasingly common and have significantly higher source impedance, are especially sensitive to these errors. Typically, a high input impedance, low bias current, FET input op amp is used to buffer the electrode signal before it is presented to an instrumentation amplifier. This buffer solves the majority of these problems; however, when an instrument is in the field, it can be subject to dust pickup and humidity. If the op amp input is not guarded, these environmental factors can create unwanted leakage currents that bring back the previous issues from input impedance that is not sufficiently high. The AD8244 is configured to make it simple to guard the inputs from parasitic resistance and capacitance while it also drives the instrumentation amplifier inputs, creating a more robust design, while saving power and board space. The CMRR of the AD8244 driving an instrumentation amplifier initially depends on the gain matching for the chosen supplies and voltage range, as well as the instrumentation amplifier used, but it can be improved with design techniques such as right leg drive (RLD) or digital filtering. FILTERING In filtering applications, it is generally recommended to use capacitors such as C0G or NP0 ceramics for distortion and dielectric absorption performance. These types of capacitors do not have a high volumetric efficiency and are available in values up to the tens of nanofarads, depending on the case size and voltage rating. For a given cutoff frequency, using smaller capacitors requires larger resistor values. At low frequencies where the resistor values become very large, the bias current of a typical op amp can introduce significant offsets and additional noise. The subpicoampere bias current of the AD8244 allows resistor values in the tens of megaohms with no additional error while providing an excellent low power, small footprint solution for filter design. Between the four channels of the AD8244, a filter with more than eight poles can be implemented while using less space than the same filter with a quad op amp. Sallen-Key Low-Pass Filter 1/4 AD8244 VOUT C1 VIN C2 R1 R2 Figure 42. Sallen-Key Low-Pass Filter The following equations describe the corner frequency, fC, and quality factor, Q, for the low-pass filter case of the Sallen-Key topology, shown in Figure 42: fC = 1/(2π C2 C1 R2 R1 × × × ) Q = ( C2 C1 R2 R1 × × × )/(C2 × (R1 + R2)) For an example of a design with this topology, choose a filter where Q = 0.707 and R1 = R2 = R. This requires that C1 = 2 × C2. The corner frequency equation can now be simplified to fC = 1/(2π × R × C2 × √2) If an available capacitor, such as 1 nF, is chosen for C2, R can be written in terms of the desired cutoff frequency: R = 1/(2√2 × π × 1 nF × fC) = 112.5 MΩ × Hz (that is, R = 750 kΩ for fC = 150 Hz) Sallen-Key High-Pass Filter 1/4 AD8244 VOUT C1 VIN C2 R1 R2 Figure 43. Sallen-Key High-Pass Filter The high-pass filter case of the Sallen-Key topology has the same corner frequency equation as the low-pass filter. However, the equation for Q changes to Q = ( C2 C1 R2 R1 × × × )/(R1 × (C1 + C2)) In this case, a Q of 0.707 is achieved with C1 = C2 = C, and R1 = ½ R2, which is a symmetrical result to the low-pass filter case. The corner frequency then simplifies to fC = 1/(√2 × π × R2 × C) For a low corner frequency, a larger available capacitor such as 22 nF can be chosen, yielding the following expression for R2: R2 = 10.2 MΩ × Hz (that is, a 0.5 Hz filter requires R1 = 10 MΩ and R2 = 20 MΩ) Rev. 0 | Page 16 of 20 |
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