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AN1059 数据表(PDF) 9 Page - STMicroelectronics

部件名 AN1059
功能描述  DESIGN EQUATIONS OF HIGH-POWER-FACTOR
PDF  20 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

AN1059 数据表(HTML) 9 Page - STMicroelectronics

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background image
ited by core saturation or losses), determining the core size, defining the primary and secondary wind-
ings (turns number and wire gauge) as well as calculating the air-gap necessary to achieve the desired
inductance. Moreover, additional considerations concerning the assembly are needed for meeting safety
requirements, maximising magnetic coupling and minimising parasitic high frequency effects, not to
mention the constraints imposed by the specific application, if any.
Some parameters are needed to start the design of the transformer. The (maximum) primary inductance
will be calculated by solving (5) for Lp:
Lp
≤
1
2
⋅
F2
(Kvmin)
1
+ Kvmin
⋅
VPKmin
2
fswmin
⋅ Pinmax
,
or by simply looking up the diagram of fig. 10, where the primary inductance required for 1W input power
is plotted against fswmin, for different values of Kvmin and for the two typical mains voltage ranges. The
value taken from fig. 10 (in mH), will be divided by the maximum input power to get the actual primary in-
ductance required by the specific application.
The primary-to-secondary turns ratio will be given by:
n
=
VR
Vout
+ Vf
.
With the peak and RMS current values calculated in the "Energetic relationships" section, the design can
be carried out just like for any conventional flyback transformer, thus no particular procedure will be con-
sidered.
Anyway, as a design aid to core selection, two expressions for determining the minimum required core
Area-Product (winding window area times effective magnetic cross section) will be provided:
APmin
=
460
⋅ Pin
fswmin
⋅ (1 + Kv) ⋅ √
F2
(Kv)
1.316
(17);
APmin
=
480
⋅ Pin
fswmin
⋅ (1 + Kv) ⋅ √
F2
(Kv)
1.585
⋅ [ JH(Kv) ⋅ fswmin + JE(Kv) ⋅ fswmin
2
]
0.66
(18);
.
2 10
4
3 10
4
4 10
4
5 10
4
6 10
4
5
25
45
65
85
L(
)
,
0.5 fmin
L(
)
,
1 fmin
L(
)
,
1.5 fmin
L(
)
,
2 fmin
L(
)
,
2.5 fmin
fmin
2 10
4
3 10
4
4 10
4
5 10
4
6 10
4
0
100
200
300
400
L(
)
,
0.5 fmin
L(
)
,
1 fmin
L(
)
,
1.5 fmin
L(
)
,
2 fmin
L(
)
,
2.5 fmin
fmin
Lmax
[mH·W]
Lmax
[mH·W]
fswmin [Hz]
fswmin [Hz]
110Vac or
Wide-range Mains
220Vac Mains
Kvmin = 0.5
1
1.5
2
2.5
Kvmin = 0.5
1
1.5
2
2.5
Figure 10. Maximum specific primary inductance required
AN1059 APPLICATION NOTE
9/20



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