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AN1495 数据表(PDF) 5 Page - STMicroelectronics

部件名 AN1495
功能描述  Microstepping stepper motor drive
PDF  25 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

AN1495 数据表(HTML) 5 Page - STMicroelectronics

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AN1495
General description
Doc ID 8700 Rev 3
5/25
Another issue occurs at low operating speeds. At low speeds, both the full and half step
drive tend to make abrupt mechanical steps since the time the rotor takes to move to the
next position can be much less than the step period. This stepping action contributes to
jerky movement and mechanical noise in the system. Looking at the simplified model of the
stepper motor in Figure 1, it can be seen that if the two coils were driven by sine and cosine
waveforms the motor would operate as a synchronous machine and run very smoothly.
These sinusoidal waveforms may be produced by a microstepping drive.
In current mode drives, the winding current is sensed and controlled to be the appropriate
value for the desired position. This application note will consider only current mode drive
implemented using peak detecting current controllers.
To understand the microstepping concept, consider the simplified model of the stepper
motor as shown in Figure 1. As previously discussed when the two coils are energized with
equal currents, the resulting magnetic vector will be at 45° and the permanent magnet of the
rotor will align with that vector. However, if the two coils are energized by currents of different
magnitude, the resulting magnetic vector will be at an angle other than 45° and the rotor
would attempt to align with the new magnetic vector. If one coil were driven with a current
that was twice the current in the second coil the magnetic vector would be at 26.56°, as
shown in Figure 3. For any given position, the required currents are defined by the sine and
cosine of the desired angle.
Figure 3.
Example alignment of microstepping
To implement a microstepping drive, two D/A converters are used to set the current level in
the coils of the motor, as shown in the block diagram in Figure 4.
IA = -1, IB=0
ΦB
Full step position
IA = IB
Half step position
IA =2 * IB
ΦA
AM15144v1



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