LMV331M5X datasheet(17/38 Pages) TI1

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TIME (µs)

C001

VOUT

LMV331-N, LMV339-N, LMV393-N

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SNOS018H – AUGUST 1999 – REVISED DECEMBER 2014

Typical Applications (continued)

If:

R1 = R2 = R3

(10)

Then:

Va1 = 2VCC/3

(11)

When the output switches to ground, the value of Va is reduced by the hysteresis network to a value given by:

Va2 = VCC/3

(12)

Capacitor C1 must now discharge through R4 towards ground. The output will return to its high state when the

voltage across the capacitor has discharged to a value equal to Va2.

For the circuit shown, the period for one cycle of oscillation will be twice the time it takes for a single RC circuit to

charge up to one half of its final value. The time to charge the capacitor can be calculated from:

(13)

Where Vmax is the max applied potential across the capacitor = (2VCC/3)

and VC = Vmax/2 = VCC/3

One period will be given by:

1/freq = 2t

(14)

or calculating the exponential gives:

1/freq = 2(0.694) R4 C1

(15)

Resistors R3 and R4 must be at least two times larger than R5 to ensure that VO will go all the way up to VCC in

the high state. The frequency stability of this circuit should strictly be a function of the external components.

8.2.1.3 Application Curve

Figure 22. Waveforms for Circuit in Typical Applications

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