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AP3595 数据表(PDF) 16 Page - Diodes Incorporated

部件名 AP3595
功能描述  DUAL PHASE SYNCHRONOUS RECTIFIED BUCK CONTROLLER
PDF  23 Pages
Scroll/Zoom Zoom In 100%  Zoom Out
制造商  DIODES [Diodes Incorporated]
网页  http://www.diodes.com
标志 DIODES - Diodes Incorporated

AP3595 数据表(HTML) 16 Page - Diodes Incorporated

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AP3595
Document number: DS36749 Rev. 1 - 2
16 of 23
www.diodes.com
January 2014
© Diodes Incorporated
AP3595
A Product Line of
Diodes Incorporated
Application Information (Cont.)
Calculate the C2 by the equation:
75
.
0
2
2
1
2
LC
f
R
C
4. Set the pole at the ESR zero frequency fESR:
ESR
P
f
f
1
Calculate the C1 by the following equation:
1
2
2
2
2
1
ESR
f
C
R
C
C
5. Set the second pole fP2 at the half of the switching frequency and also set the second zero fZ2 at the output LC filter double pole fLC. The
compensation gain should not exceed the error amplifier open loop gain. Check the compensation gain at fP2 with the capabilities of the error
amplifier.
LC
Z
SW
P
f
f
f
f
2
2
5
.
0
Combine the two equations will get the following component calculations:
1
2
1
3
LC
SW
f
f
R
R
SW
f
R
C
3
1
3
Figure 10.Converter Gain and Frequency
14. Output Inductor Selection
The duty cycle (D) of a buck converter is the function of the input voltage and output voltage. Once an output voltage is fixed, it can be written as:
IN
OUT
V
V
D
/
For two-phase converter, the inductor value (L)
determines the sum of the two inductor ripple current, ΔIP-P, and affects the load transient
response. Higher inductor value
reduces the output capacitors’ ripple current and induces lower output ripple voltage. The ripple current can be
approximated by:
IN
OUT
SW
OUT
IN
P
P
V
V
L
f
V
V
I
2
Where fSW is the switching frequency of the regulator.



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