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LOG112 数据表(PDF) 12 Page - Texas Instruments |
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LOG112 数据表(HTML) 12 Page - Texas Instruments |
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12 / 14 page ![]() LOG112, 2112 12 SBOS246C www.ti.com ERRORS RTO AND RTI As with any transfer function, errors generated by the func- tion may be Referred-to-Output (RTO) or Referred-to-Input (RTI). In this respect, log amps have a unique property: given some error voltage at the log amp’s output, that error corre- sponds to a constant percent of the input regardless of the actual input level. LOG CONFORMITY For the LOG112 and LOG2112, log conformity is calculated the same as linearity and is plotted I1/I2 on a semi-log scale. In many applications, log conformity is the most important specification. This is true because bias current errors are negligible (5pA compared to input currents of 100pA and above) and the scale factor and offset errors may be trimmed to zero or removed by system calibration. This leaves log conformity as the major source of error. Log conformity is defined as the peak deviation from the best fit straight line of the VLOGOUT versus log (I1/I2) curve. This is expressed as a percent of ideal full-scale output. Thus, the nonlinearity error expressed in volts over m decades is: VLOGOUT (NONLIN) = 0.5V/dec • 2NmV (7) where N is the log conformity error, in percent. INDIVIDUAL ERROR COMPONENTS The ideal transfer function with current input is: V V LOG I I LOGOUT = ( ) 05 1 2 . (8) The actual transfer function with the major components of error is: VV K II II Nm V LOGOUT B B OSO = ( ) ± ( ) ±± 05 1 1 1 2 2 . log – – ∆ (9) The individual component of error is: ∆K = gain error (0.10%, typ), as specified in the specifica- tion table. IB1 = bias current of A1 (5pA, typ) IB2 = bias current of A2 (5pA, typ) N = log conformity error (0.01%, 0.13%, typ) 0.01% for m = 5, 0.13% for m = 7.5 VOSO = output offset voltage (3mV, typ) m = number of decades over which N is specified For example, what is the error when: I1 = 1µA and I2 = 100nA (10) (11) VmV V LOGOUT =± ( ) − − ± ( )( ) ± = −− −− 05 0001 10 5 10 10 5 10 2 0 0001 5 3 0 0 505 612 712 . . log • • .. . Since the ideal output is 0.5V, the error as a percent of the reading is: % . . %. % error V =• = 0 505 05 100 1 01 (12) For the case of voltage inputs, the actual transfer function is: (13) VV K V R I E R V R I E R Nm V LOGOUT B OS B OS OSO = ( ) ± ( ) ± ± ±± 05 1 1 11 2 22 1 1 2 2 . log – – ∆ Where E R and E R OS OS 1 1 2 2 (offset error) are considered to be zero for large values of resistance from external input current sources. |
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