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AST1S31HF 数据表(PDF) 22 Page - STMicroelectronics

部件名 AST1S31HF
功能描述  Internal soft-start and enable
PDF  33 Pages
Scroll/Zoom Zoom In 100%  Zoom Out
制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

AST1S31HF 数据表(HTML) 22 Page - STMicroelectronics

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Application information
AST1S31HF
22/33
DocID026968 Rev 2
7.4
Thermal dissipation
The thermal design is important to prevent the thermal shutdown of the device if junction
temperature goes above 150 °C. The three different sources of losses within the device are:
a)
Conduction losses due to the on-resistance of the high-side switch (RHS) and low-
side switch (RLS); these are equal to:
Equation 33
where D is the duty cycle of the application. Note that the duty cycle is theoretically given by
the ratio between VOUT and VIN, but it is actually slightly higher to compensate the losses of
the regulator.
b)
Switching losses due to the high-side power MOSFET turn-on and turn-off; these
can be calculated as:
Equation 34
where TRISE and TFALL are the overlap times of the voltage across the high-side power
switch (VDS) and the current flowing into it during the turn-on and turn-off phases, as shown
in Figure 9. TSW is the equivalent switching time. For this device the typical value for the
equivalent switching time is 20 ns.
c)
Quiescent current losses, calculated as:
Equation 35
where IQ is the quiescent current (IQ = 1.2 mA maximum).
The junction temperature TJ can be calculated as:
Equation 36
where TA is the ambient temperature and PTOT is the sum of the power losses just seen.
RthJA is the equivalent thermal resistance junction to ambient of the device; it can be
calculated as the parallel of many paths of heat conduction from the junction to the ambient.
For this device the path through the exposed pad is the one conducting the largest amount
of heat. The RthJA measured on the demonstration board (see Figure 12 on page 26) is
about 50 °C/W.
PCOND
RHS IOUT
2 DR
LS IOUT
2
1D


+

=
PSW
VIN IOUT
TRISE TFALL
+

2
------------------------------------------- Fsw

VIN IOUT TSW FSW

==
PQ
VIN IQ
=
TJ
TA RthJA PTOT
+
=



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