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L5953 数据表(PDF) 21 Page - STMicroelectronics

部件名 L5953
功能描述  MULTIPLE SWITCHING VOLTAGE REGULATOR
PDF  24 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

L5953 数据表(HTML) 21 Page - STMicroelectronics

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L5953
and a resistive contribute given by the ESR of the capacitor and which is equal to
∆VC fixes the value for C7 while ∆VESR limits the ESR of the capacitor.Usually the capacitor is chosen so that
the total ripple on the output regulated voltage Vo is equal to 1% of the value of Vo. If Vripple is the maximum
allowed voltage ripple on Vo then it should result:
More often the minimum value of C7 is imposed by other considerations such as to get a good dynamic behav-
iour of the output voltage in case of large load variations.
Free-wheeling diode
The diode must withstand an average current Id equal to Id = Ilim ( 1- Dmin )
where Ilim is the current of intervention of the short circuit protection and Dmin is the minimum duty cycle. As Dmin
is vey low, the current Id can be assumed equal to Ilim.
Compensation Network
In continuous mode, the voltage controlled buck converter showes two poles due to the output LC filter and one
zero due to the ESR of the output capacitor. The suggested compensation network introduces two zeros and
two poles:
– the zeros compensate the double poles of the LC filter
– one pole compensates the zero due to ESR of the output capacitor
– the second pole is nominally located in the origin which means an infinite gain at frequency null. In
the reality the DC value of the closed loop gain can not be greater than the DC value of the EA open
loop gain and the pole is located at very low frequency.
The values for the components of the compensation network can be fixed when the inductor L1 and the output
capacitor C7 are chosen.
The necessary steps are following:
1.fix the cross-over frequency fC of the overall loop gain.
Usually
where fsw,min is the minimum switching frequency
2.Calculate the high frequency error amplifier gain
3.Chose R3 and calculate
The value for R3 has not to be very high (for example 10K
Ω) so to limit the error due to an error amplifier input
offset current.
∆V
c
∆I
Lm ax
,
8C7 f
sw m in
,
⋅⋅
---------------------------------------
=
∆V
ESR
ESR
∆I
Lm a x
,
=
V
ri ppl e
∆V
c
2
∆V
ES R
2
+
f
c
0.1 f
sw,min
=
G
c
0.25 f
c
2
π
L1
ESR
-------------
⋅⋅ ⋅ ⋅
=
C8
2
L1 C7
R3
-----------------------
=



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