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TC2575 数据表(PDF) 17 Page - TelCom Semiconductor, Inc |
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TC2575 数据表(HTML) 17 Page - TelCom Semiconductor, Inc |
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17 / 25 page ![]() 17 TC2575 TC2575-1 3/13/00 1.0A Step-Down Switching Regulator ADDITIONAL APPLICATIONS Inverting Regulator An inverting buck–boost regulator using the TC2575 (12V) is shown in Figure 8. This circuit converts a positive input voltage to a negative output voltage with a common ground by bootstrapping the regulators ground to the negative output voltage. By grounding the feedback pin, the regulator senses the inverted output voltage and regu- lates it. In this example the TC2575 (12V) is used to generate a 12V output. The maximum input voltage in this case cannot exceed 28V because the maximum voltage appearing across the regulator is the absolute sum of the input and output voltages and this must be limited to a maximum of 40V. This circuit configuration is able to deliver approximately 0.35A to the output when the input voltage is 12V or higher. At lighter loads the minimum input voltage required drops to approximately 4.7V, because the buck–boost regulator to- pology can produce an output voltage that, in its absolute value, is either greater or less than the input voltage. Since the switch currents in this buck–boost configura- tion are higher than in the standard buck converter topology, the available output current is lower. This type of buck–boost inverting regulator can also require a larger amount of startup input current, even for light loads. This may overload an input power source with a current limit less than 1.5A. Such an amount of input start-up current is needed for at least 2.0msec or more. The actual time depends on the output voltage and size of the output capacitor. Because of the relatively high startup currents required by this inverting regulator topology, the use of a delayed startup or an undervoltage lockout circuit is recommended. Using a delayed startup arrangement, the input capaci- tor can charge up to a higher voltage before the switch– mode regulator begins to operate. The high input current needed for startup is now partially supplied by the input capacitor CIN. Design Recommendations: The inverting regulator operates in a different manner than the buck converter and so a different design procedure has to be used to select the inductor L1 or the output capacitor COUT. The output capacitor values must be larger than what is normally required for buck converter designs. Low input voltages or high output currents require a large value output capacitor (in the range of thousands of µF). The recommended range of inductor values for the inverting converter design is between 68 µH and 220 µH. To select an inductor with an appropriate current rating, the inductor peak current has to be calculated. The following formula is used to obtain the peak inductor current: IPEAK ≈ ILOAD (VIN – IVOUTI) + VIN x tON VIN 2L1 where tON ≈ IVOUTI 1.0 , and fOSC = 52kHz. VIN + IVOUTI x fOSC Under normal continuous inductor current operating conditions, the worst case occurs when VIN is minimal. Note that the voltage appearing across the regulator is the absolute sum of the input and output voltage, and must not exceed 40V. It has been already mentioned above, that in some situations, the delayed startup or the undervoltge lockout features could be very useful. A delayed startup circuit applied to a buck-boost converter is shown in Figure 9. Figure 15 in the "Undervoltage Lockout" section describes an undervoltage lockout feature for the same converter topology. Figure 9. Inverting Buck-Boost Regulator with Delayed Startup D1 1N5819 L1 100 µH Output GND 2 3 4 Feedback 12 to 25V Unregulated DC Input 1 C1 0.1 µF 5 R1 47k R2 47k ON/OFF +VIN –12V @ 0.35A Regulated Output TC2575 (12V) COUT 1800 µF/16V CIN 100 µF /50V TC2575 1 3 5 GND ON/OFF +VIN R2 47k CIN 100 µF NOTE: This picture does not show the complete circuit. R1 47 k R3 470 Shutdown Input MOC8101 –VOUT Off On 5.0V 0 +VIN Figure 10. Inverting Buck-Boost Regulator Shutdown Circuit Using an Optocoupler |
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