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ADP1621ARMZ-R7 数据表(PDF) 14 Page - Analog Devices |
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ADP1621ARMZ-R7 数据表(HTML) 14 Page - Analog Devices |
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14 / 32 page ![]() ADP1621 Data Sheet Rev. D | Page 14 of 32 APPLICATION INFORMATION: BOOST CONVERTER In this section, an analysis of a boost converter is presented, along with guidelines for component selection. A typical boost- converter application circuit is shown in Figure 1. ADIsimPower DESIGN TOOL The ADP1621 is supported by ADIsimPower design tool set. ADIsimPower is a collection of tools that produce complete power designs optimized for a specific design goal. The tools enable the user to generate a full schematic, bill of materials, and calculate performance in minutes. ADIsimPower can optimize designs for cost, area, efficiency, and device count while taking into consideration the operating conditions and limitations of the IC and all real external components. For more information about ADIsimPower design tools, refer to www.analog.com/ADIsimPower. The tool set is available from this website, and users can also request an unpopulated board through the tool. DUTY CYCLE To determine the worst-case inductor current ripple, output voltage ripple, and slope-compensation factor, it is first necessary to determine the system duty cycle. The duty cycle in continuous conduction mode (CCM) is calculated by the following equation: D OUT IN D OUT V V V V V D + − + = (1) where: VOUT is the desired output voltage. VIN is the input voltage. VD is the forward-voltage drop of the diode. A typical Schottky diode has a forward-voltage drop of 0.5 V. The GATE minimum on and off times determine the minimum and maximum duty cycles, respectively. The minimum on and off times are typically 180 ns and 190 ns, respectively. The minimum and maximum duty cycles are given by the following equations: SW MIN ON SW MIN ON MIN f t t t D × = = , , (2) ) ( 1 1 , , SW MIN OFF SW MIN OFF MAX f t t t D × − = − = (3) where: DMIN is the minimum duty cycle. DMAX is the maximum duty cycle. tON,MIN is the minimum on time. tOFF,MIN is the minimum off time. tSW is the switching period. fSW is the switching frequency. Note that when the converter tries to operate at a duty cycle lower than DMIN, pulse-skipping modulation occurs to maintain the output voltage regulation (see the Light Load Operation section). SETTING THE OUTPUT VOLTAGE The output voltage is set through a voltage divider from the output voltage to the FB input. The feedback resistor ratio sets the output voltage of the system. The regulation voltage at FB is 1.215 V. The output voltage is given by the following equation (see Figure 1): + × = R2 R1 VOUT 1 V 215 . 1 (4) The input bias current into FB is 25 nA typical, 70 nA maximum. For a 0.1% degradation in regulation voltage and with 70 nA bias current, R2 must be less than 18 kΩ, which results in 68 µA of divider current. Choose the value of R1 to set the output voltage. Using higher values for R2 results in reduced output voltage accuracy due to the input bias current at the FB pin, whereas lower values cause increased quiescent current consumption. INDUCTOR CURRENT RIPPLE Choose a peak-to-peak inductor ripple current between 20% and 40% of the average inductor current. A good starting point for a design is to choose the peak-to-peak ripple current to be 30% of 1/(1 − D) times the maximum load current: D I I MAX LOAD L − × = ∆ 1 3 . 0 , (5) where: ΔIL is the peak-to-peak inductor ripple current. ILOAD,MAX is the maximum load current required by the application. INDUCTOR SELECTION The inductor value choice is important because it dictates the inductor current ripple and therefore the voltage ripple at the output. The average inductor current, IL,AVE, is given by the following equation: D I I LOAD AVE L − = 1 , (6) and the peak-to-peak inductor ripple current is inversely proportional to the inductor value: L f D V I SW IN L × × = ∆ (7) where: fSW is the switching frequency. L is the inductor value. Assuming continuous conduction mode (CCM) operation, the peak inductor current is given by the following equation: L f D V D I I D I I SW IN LOAD L LOAD PK L × × × + − = ∆ + − = 2 1 2 1 , (8) |
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