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LT8650SPJVPBF 数据表(PDF) 17 Page - Analog Devices

部件名 LT8650SPJVPBF
功能描述  Dual Channel 6A, 42V, Synchronous Step-Down Silent Switcher 2 with 6.2μA Quiescent Current
PDF  34 Pages
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制造商  AD [Analog Devices]
网页  http://www.analog.com
标志 AD - Analog Devices

LT8650SPJVPBF 数据表(HTML) 17 Page - Analog Devices

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LT8650SP
17
Rev. B
For more information www.analog.com
APPLICATIONS INFORMATION
Table 1. SW Frequency vs RT Value
fSW (MHz)
RT (kΩ)
0.3
137
0.4
100
0.5
78.7
0.6
63.4
0.8
46.4
1.0
35.7
1.2
28.7
1.4
23.7
1.6
20
1.8
17.4
2.0
15
2.2
13
2.5
11
3.0
8.06
Operating Frequency Selection and Trade-Offs
Selection of the operating frequency is a trade-off between
efficiency, component size, and input voltage range. The
advantageofhighfrequencyoperationisthatsmallerinduc-
tor and capacitor values may be used. The disadvantages
are lower efficiency and a smaller input voltage range.
The highest switching frequency (fSW(MAX)) for a given
application can be calculated as follows:
fSW(MAX)=
VOUT +VSW(BOT)
tON(MIN) VIN – VSW(TOP)+VSW(BOT)
(
)
where VIN is the typical input voltage, VOUT is the output
voltage, VSW(TOP) and VSW(BOT) are the internal switch
drops (~0.3V, ~0.12V, respectively at maximum load) and
tON(MIN) is the minimum top switch on-time of 60ns (see
the Electrical Characteristics). This equation shows that a
slower switching frequency is necessary to accommodate
a high VIN/VOUT ratio. Choose the switching frequency
basedonwhichchannelhasthelowerfrequencyconstraint.
For transient operation, VINmaygoashighastheabsolute
maximumratingof42VregardlessoftheRTvalue,however
the LT8650SP will reduce switching frequency on each
channel independently as necessary to maintain control
of inductor current to assure safe operation.
divider. The current flowing in the divider acts as a load
current, and will increase the no-load input current to the
converter, which is approximately:
IQ = 3.7µA+
VOUT1
R1
+R2
⎛
⎝⎜
⎞
⎠⎟
VOUT1
VIN1
⎛
⎝⎜
⎞
⎠⎟
1
n
⎛
⎝⎜
⎞
⎠⎟
where 3.7µA is the quiescent current of channel 1 and
common circuitries, the second term is the current in the
feedback divider reflected to the input of channel 1 oper-
ating at its light load efficiency n. For a 3.3V application
with R1 = 1M and R2 = 316k, the feedback divider draws
2.5µA. With VIN = 12V and n = 80%, this adds 0.9µA to the
3.7µAquiescentcurrentresultingin4.6µAno-loadcurrent
from the 12V supply. Note that this equation implies that
the no-load current is a function of VIN; this is plotted in
the Typical Performance Characteristics section.
A similar calculation can be done to determine the input
current contribution from the channel 2 feedback resis-
tors. For a 5V application with R3 = 1M, R4 = 191k, VIN
= 12V, and h = 80%, this adds 2.2µA to the input current
resulting in a total of 6.8µA with both channels on.
For a typical FB resistor of 1M, a 4.7pF to 10pF phase-lead
capacitor should be connected from VOUT to FB.
Setting the Switching Frequency
The LT8650SP uses a constant frequency PWM architec-
ture that can be programmed to switch from 300kHz to
3MHz by using a resistor tied from the RT pin to ground.
Table 1 shows the necessary RTvalueforadesiredswitch-
ing frequency.
The RT resistor required for a desired switching frequency
can be calculated using:
RT =
41.7
fSW
– 5.8
where RT is in kΩ and fSW is the desired switching fre-
quency in MHz.
The two channels of the LT8650SP operate 180° out of
phase to avoid aligned switching edge noise and reduce
input current ripple.



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