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TPA3003D2 数据表(PDF) 16 Page - Texas Instruments |
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TPA3003D2 数据表(HTML) 16 Page - Texas Instruments |
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16 / 34 page ![]() TPA3003D2 SLOS406A − FEBRUARY 2003 − REVISED MARCH 2003 16 www.ti.com APPLICATION INFORMATION TPA3003D2 modulation scheme (continued) 0 V −12 V +12 V Current OUTP OUTN Differential Voltage Across Load 0 V −12 V +12 V Current OUTP OUTN Differential Voltage Across Load Output = 0 V Output > 0 V Figure 23. The TPA3003D2 Output Voltage and Current Waveforms Into an Inductive Load efficiency: LC filter required with the traditional class-D modulation scheme The main reason that the traditional class-D amplifier needs an output filter is that the switching waveform results in maximum current flow. This causes more loss in the load, which causes lower efficiency. The ripple current is large for the traditional modulation scheme, because the ripple current is proportional to voltage multiplied by the time at that voltage. The differential voltage swing is 2 × VCC, and the time at each voltage is half the period for the traditional modulation scheme. An ideal LC filter is needed to store the ripple current from each half cycle for the next half cycle, while any resistance causes power dissipation. The speaker is both resistive and reactive, whereas an LC filter is almost purely reactive. The TPA3003D2 modulation scheme has very little loss in the load without a filter because the pulses are very short and the change in voltage is VCC instead of 2 × VCC. As the output power increases, the pulses widen, making the ripple current larger. Ripple current could be filtered with an LC filter for increased efficiency, but for most applications the filter is not needed. An LC filter with a cutoff frequency less than the class-D switching frequency allows the switching current to flow through the filter instead of the load. The filter has less resistance than the speaker, which results in less power dissipation, therefore increasing efficiency. |
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