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AD8310 数据表(PDF) 15 Page - Analog Devices |
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AD8310 数据表(HTML) 15 Page - Analog Devices |
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15 / 24 page ![]() AD8310 Rev. F | Page 15 of 24 INPUT LEVEL (dBV) –5 –120 20 –100 (–87dBm) –80 –60 –40 –20 0 (+13dBm) 5 4 –1 –2 –3 –4 2 0 3 1 10MHz 50MHz 100MHz ±3dB DYNAMIC RANGE ±1dB DYNAMIC RANGE Figure 30. Log Conformance Error vs. Input Level at 10 MHz, 50 MHz, and 100 MHz TRANSFER FUNCTION IN TERMS OF SLOPE AND INTERCEPT The transfer function of the AD8310 is characterized in terms of its slope and intercept. The logarithmic slope is defined as the change in the RSSI output voltage for a 1 dB change at the input. For the AD8310, slope is nominally 24 mV/dB. Therefore, a 10 dB change at the input results in a change at the output of approximately 240 mV. The plot of log conformance shows the range over which the device maintains its constant slope. The dynamic range of the log amp is defined as the range over which the slope remains within a certain error band, usually ±1 dB or ±3 dB. In Figure 30, for example, the ±1 dB dynamic range is approximately 95 dB (from +4 dBV to −91 dBV). The intercept is the point at which the extrapolated linear response would intersect the horizontal axis (see Figure 29). For the AD8310, the intercept is calibrated to be −108 dBV (−95 dBm). Using the slope and intercept, the output voltage can be calculated for any input level within the specified input range using the following equation: VOUT = VSLOPE × (PIN − PO) (3) where: VOUT is the demodulated and filtered RSSI output. VSLOPE is the logarithmic slope expressed in V/dB. PIN is the input signal expressed in dB relative to some reference level (either dBm or dBV in this case). PO is the logarithmic intercept expressed in dB relative to the same reference level. For example, for an input level of −33 dBV (−20 dBm), the output voltage is VOUT = 0.024 V/dB × (−33 dBV − (−108 dBV)) = 1.8 V (4) dBV vs. dBm The most widely used convention in RF systems is to specify power in dBm, decibels above 1 mW in 50 Ω. Specification of the log amp input level in terms of power is strictly a concession to popular convention. As mentioned previously, log amps do not respond to power (power absorbed at the input), but to the input voltage. The use of dBV, defined as decibels with respect to a 1 V rms sine wave, is more precise. However, this is still ambiguous, because waveform is also involved in the response of a log amp, which, for a complex input such as a CDMA signal, does not follow the rms value exactly. Because most users specify RF signals in terms of power (more specifically, in dBm/50 Ω) both dBV and dBm are used to specify the perform- ance of the AD8310, showing equivalent dBm levels for the special case of a 50 Ω environment. Values in dBV are converted to dBm re 50 Ω by adding 13 dB. Table 4. Correction for Signals with Differing Crest Factors Signal Type Correction Factor1 (dB) Sine wave 0 Square wave or dc −3.01 Triangular wave 0.9 GSM channel (all time slots on) 0.55 CDMA channel (forward link, nine channels on) 3.55 CDMA channel (reverse link) 0.5 PDC channel (all time slots on) 0.58 1 Add to the measured input level. INPUT MATCHING Where higher sensitivity is required, an input matching network is useful. Using a transformer to achieve the impedance trans- formation also eliminates the need for coupling capacitors, lowers the offset voltage generated directly at the input, and balances the drive amplitude to INLO and INHI. The choice of turns ratio depends somewhat on the frequency. At frequencies below 50 MHz, the reactance of the input capacitance is much higher than the real part of the input impedance. In this frequency range, a turns ratio of about 1:4.8 lowers the input impedance to 50 Ω, while raising the input voltage lowers the effect of the short-circuit noise voltage by the same factor. The intercept is also lowered by the turns ratio; for a 50 Ω match, it is reduced by 20 log10 (4.8) or 13.6 dB. The total noise is reduced by a somewhat smaller factor, because there is a small contribution from the input noise current. |
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