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TLC27L4CPWR 数据表(PDF) 30 Page - Texas Instruments

部件名 TLC27L4CPWR
功能描述  LinCMOSE PRECISION QUAD OPERATIONAL AMPLIFIERS
PDF  43 Pages
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制造商  TI2 [Texas Instruments]
网页  https://www.ti.com
标志 TI2 - Texas Instruments

TLC27L4CPWR 数据表(HTML) 30 Page - Texas Instruments

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TLC27L4, TLC27L4A, TLC27L4B, TLC27L4Y, TLC27L9
LinCMOS
™ PRECISION QUAD OPERATIONAL AMPLIFIERS
SLOS053C – OCTOBER 1987 – REVISED AUGUST 1994
30
POST OFFICE BOX 655303
• DALLAS, TEXAS 75265
APPLICATION INFORMATION
single-supply operation
While the TLC27L4 and TLC27L9 perform well using dual power supplies (also called balanced or split
supplies), the design is optimized for single-supply operation. This design includes an input common-mode
voltage range that encompasses ground as well as an output voltage range that pulls down to ground. The
supply voltage range extends down to 3 V (C-suffix types), thus allowing operation with supply levels commonly
available for TTL and HCMOS; however, for maximum dynamic range, 16-V single-supply operation is
recommended.
Many single-supply applications require that a voltage be applied to one input to establish a reference level that
is above ground. A resistive voltage divider is usually sufficient to establish this reference level (see Figure 38).
The low input bias current of the TLC27L4 and TLC27L9 permits the use of very large resistive values to
implement the voltage divider, thus minimizing power consumption.
The TLC27L4 and TLC27L9 work well in conjunction with digital logic; however, when powering both linear
devices and digital logic from the same power supply, the following precautions are recommended:
1.
Power the linear devices from separate bypassed supply lines (see Figure 39); otherwise, the linear
device supply rails can fluctuate due to voltage drops caused by high switching currents in the digital
logic.
2.
Use proper bypass techniques to reduce the probability of noise-induced errors. Single capacitive
decoupling is often adequate; however, high-frequency applications may require RC decoupling.
R4
VO
VDD
R2
R1
VI
VREF
R3
C
0.01
µF
VREF = VDD
R3
R1 + R3
VO = (VREF – VI )
R4
R2
+ VREF
Figure 38. Inverting Amplifier With Voltage Reference



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