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LED7707 数据表(PDF) 27 Page - STMicroelectronics

部件名 LED7707
功能描述  6-rows 85 mA LEDs driver with boost regulator for LCD panels backlight
PDF  48 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

LED7707 数据表(HTML) 27 Page - STMicroelectronics

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LED7707
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Equation 13b
Where VIN,min is the minimum input voltage and IOUT is the overall output current.
Note that, the lower the inductor value (and the higher the switching frequency), the higher
the bandwidth can be achieved. The output capacitor is directly involved in the loop of the
boost converter and must be large enough to avoid excessive output voltage drop in case of
a sudden line transition from the maximum to the minimum input voltages.
However a more significant requirement concerns the output voltage ripple.
The output capacitor should be chosen in accordance with the following expression:
Equation 14
where
ΔV
OUT, max is the maximum acceptable output voltage ripple, IL, peak is the peak
inductor current, TOFF is the off-time of the switching cycle (for an extensive explanation see
Section 6.4.4 on page 34
).
Once the output capacitor has been chosen, the RCOMP can be calculated as:
Equation 15
Where GM = 2.7 S and gEA = 375 µS
Equation 15 places the loop bandwidth at fU. Then, the CCOMP capacitor is determined to
place the frequency of the compensation zero 5 times lower than the loop bandwidth:
Equation 16
Where fZ = fU/5.
In most of the applications an experimental approach is also very valid to compensate the
circuit. A simple technique to optimize different applications is to choose CCOMP = 4.7 nF
and to replace RCOMP with a 10 kΩ trimmer adjusting its value to properly damp the output
transient response. Insufficient damping will result in excessive ringing at the output and
poor phase margin.
Figure 18
(a and b) give an example of compensation adjustment for a typical application.
OUT
OUT
I
V
R
=
(
)
max
,
OUT
OFF
OUT
peak
,
L
OUT
V
2
T
I
I
C
Δ
>
M
g
G
C
f
2
R
EA
M
U
COMP
π
=
COMP
Z
COMP
R
f
2
1
C
π
=



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