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TS4902 数据表(PDF) 16 Page - STMicroelectronics |
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TS4902 数据表(HTML) 16 Page - STMicroelectronics |
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16 / 19 page ![]() TS4902 16/19 The efficiency is the ratio between the output power and the power supply The maximum theoretical value is reached when Vpeak = Vcc, so s Decoupling of the circuit Two capacitors are needed to bypass properly the TS4902, a power supply bypass capacitor Cs and a bias voltage bypass capacitor Cb. Cs has especially an influence on the THD+N in high frequency (above 7kHz) and indirectly on the power supply disturbances. With 100µF, you can expect similar THD+N performances like shown in the datasheet. If Cs is lower than 100µF, in high frequency increases, THD+N and disturbances on the power supply rail are less filtered. To the contrary, if Cs is higher than 100µF, those disturbances on the power supply rail are more filtered. Cb has an influence on THD+N in lower frequency, but its function is critical on the final result of PSRR with input grounded in lower frequency. If Cb is lower than 1µF, THD+N increase in lower frequency (see THD+N vs frequency curves) and the PSRR worsens up If Cb is higher than 1µF, the benefit on THD+N in lower frequency is small but the benefit on PSRR is substantial (see PSRR vs. Cb curve : fig.12). Note that Cin has a non-negligible effect on PSRR in lower frequency. Lower is its value, higher is the PSRR (see fig. 13). s Pop and Click performance Pop and Click performance is intimately linked with the size of the input capacitor Cin and the bias voltage bypass capacitor Cb. Size of Cin is due to the lower cut-off frequency and PSRR value requested. Size of Cb is due to THD+N and PSRR requested always in lower frequency. Moreover, Cb determines the speed that the amplifier turns ON. The slower the speed is, the softer the turn ON noise is. The charge time of Cb is directly proportional to the internal generator resistance 50k Ω. Then, the charge time constant for Cb is τb = 50kΩxCb (s) As Cb is directly connected to the non-inverting input (pin 2 & 3) and if we want to minimize, in amplitude and duration, the output spike on Vout1 (pin 5), Cin must be charged faster than Cb. The charge time constant of Cin is τin = (Rin+Rfeed)xCin (s) Thus we have the relation τin << τb (s) The respect of this relation permits to minimize the pop and click noise. Remark : Minimize Cin and Cb has a benefit on pop and click phenomena but also on cost and size of the application. Example : your target for the -3dB cut off frequency is 100 Hz. With Rin=Rfeed=22 k Ω, Cin=72nF (in fact 82nF or 100nF). With Cb=1µF, if you choose the one of the latest two values of Cin, the pop and click phenomena at power supply ON or standby function ON/OFF will be very small 50 k Ωx1µF >> 44kΩx100nF (50ms >> 4.4ms). Increasing Cin value increases the pop and click phenomena to an unpleasant sound at power supply ON and standby function ON/OFF. Why Cs is not important in pop and click consideration ? Hypothesis : • Cs = 100µF • Supply voltage = 5V • Supply voltage internal resistor = 0.1 Ω • Supply current of the amplifier Icc = 6mA At power ON of the supply, the supply capacitor is charged through the internal power supply resistor. So, to reach 5V you need about five to ten times the charging time constant of Cs ( τs = 0.1xCs (s)). Then, this time equal 50µs to 100µs << τb in the majority of application. η = POUT Psup pl y ------------------------ = πVPEAK 4VCC ----------------------- π 4 ----- = 78.5% |
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