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TS616 数据表(PDF) 25 Page - STMicroelectronics

部件名 TS616
功能描述  DUAL WIDE BAND OPERATIONAL AMPLIFIER WITH HIGH OUTPUT CURRENT
PDF  27 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

TS616 数据表(HTML) 25 Page - STMicroelectronics

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Component Calculation
Let us consider the equivalent circuit for a sin-
gle-ended configuration as shown in Figure 69.
Figure 69: Single ended equivalent circuit
Let us consider the unloaded system. Assuming
the currents through R1, R2 and R3
are respectively:
as Vo° equals Vo without load, the gain in this
case becomes :
The gain, for the loaded system will be (eq1):
As shown in Figure70, this system is an ideal gen-
erator with a synthesized impedance as the inter-
nal impedance of the system. From this, the out-
put voltage becomes:
with Ro the synthesized impedance and Iout the
output current. On the other hand Vo can be ex-
pressed as:
By identification of both equations (eq2) and
(eq3),
the
synthesized
impedance
is,
with
Rs1=Rs2=Rs:
Figure 70: Equivalent schematic. Ro is the
synthesized impedance.
Unlike the level Vo° required for a passive imped-
ance, Vo° will be smaller than 2Vo in our case. Let
us write Vo°=kVo with k the matching factor vary-
ing between 1 and 2. Assuming that the current
through R3 is negligible, (eq4) becomes the fol-
lowing :
After choosing the k factor, Rs will equal to
1/2RL(k-1).
A good impedance matching assumes:
(eq4) and (eq5) give :
By fixing an arbitrary value of R2, (eq6) becomes :
Finally, the values of R2 and R3 allow us to extract
R1 from (eq1), and it becomes:
R2
R3
+
_
Vi
Vo
Rs1
-1
Vo°
+
_
-1
½ RL
½ R1
R2
R3
+
_
Vi
Vo
Rs1
-1
Vo°
+
_
-1
½ RL
½ R1
2Vi
R1
---------
Vi
Vo
°
()
R2
--------------------------- and
Vi
Vo
+
()
R3
------------------------
,
G
Vo noload
()
Vi
---------------------------------
1
2R2
R1
-----------
R2
R3
--------
++
1
R2
R3
--------
------------------------------------
==
GL
Vo with load
()
Vi
--------------------------------------
1
2
---
1
2R2
R1
-----------
R2
R3
--------
++
1
R2
R3
--------
------------------------------------ eq1
()
,
==
Vo
ViG
()
RoIout
()
=
eq2
()
,
Vo
Vi 1
2R2
R1
-----------
R2
R3
--------
++


1
R2
R3
--------
------------------------------------------------
Rs1Iout
1
R2
R3
--------
----------------------- eq3
()
,
=
Ro
Rs
1
R2
R3
--------
----------------- eq4
()
,
=
Ro
Vi.Gi
Iout
1/2
RL
Ro
kV oRL
RL
2R s1
+
------------------------------
=
Ro
1
2
--- RL eq5
()
,
=
R2
R3
--------1
2Rs
RL
----------- eq6
()
,
=
R3
R2
1
2Rs
RL
-----------
---------------------
=



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