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MIC5167 数据表(PDF) 13 Page - Micrel Semiconductor |
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MIC5167 数据表(HTML) 13 Page - Micrel Semiconductor |
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13 / 23 page ![]() Micrel, Inc. MIC5167 January 2012 13 M9999-012312-B Inductor Selection Inductor selection will be determined by the following (not necessarily in the order of importance): • Inductance • Rated current value • Size requirements • DC resistance (DCR) The MIC5167 is designed for use with a 0.4µH to 4.7µH inductor. Maximum current ratings of the inductor are generally given in two methods: permissible DC current and saturation current. Permissible DC current can be rated either for a 40°C temperature rise or a 10% loss in inductance. Ensure the inductor selected can handle the maximum operating current. When saturation current is specified, make sure that there is enough margin that the peak current will not saturate the inductor. The ripple current can add as much as 1.2A to the output current level. The RMS rating should be chosen to be equal or greater than the Current Limit of the MIC5167 to prevent overheating in a fault condition. For best electrical performance, the inductor should be placed very close to the SW nodes of the IC. For this reason, the heat of the inductor is somewhat coupled to the IC, so it offers some level of protection if the inductor gets too hot. It is important to test all operating limits before settling on the final inductor choice. The size requirements refer to the area and height requirements that are necessary to fit a particular design. Please refer to the inductor dimensions on their datasheet. DC resistance is also important. While DCR is inversely proportional to size, DCR can represent a significant efficiency loss. Refer to the “Efficiency Considerations” below for a more detailed description. Efficiency Considerations Efficiency is defined as the amount of useful output power, divided by the amount of power consumed. 100 I V I V % Efficiency IN IN OUT OUT × ⎟⎟ ⎠ ⎞ ⎜⎜ ⎝ ⎛ × × = Maintaining high efficiency serves two purposes. It decreases power dissipation in the power supply, reducing the need for heat sinks and thermal design considerations and it decreases consumption of current for battery powered applications. Reduced current draw from a battery increases the devices operating time, critical in hand held devices. There are mainly two loss terms in switching converters: static losses and switching losses. Static losses are simply the power losses due to VI or I 2R. For example, power is dissipated in the high-side switch during the on cycle. Power loss is equal to the high-side MOSFET RDS(ON) multiplied by the RMS Switch Current squared (ISW 2). During the off-cycle, the low-side N-Channel MOSFET conducts, also dissipating power. Similarly, the inductor’s DCR and capacitor’s ESR also contribute to the I 2R losses. Device operating current also reduces efficiency by the product of the quiescent (operating) current and the supply voltage. The current required to drive the gates on and off at a constant 1MHz frequency and the switching transitions make up the switching losses. Figure 4 shows an efficiency curve. The portion, from 0A to 1A, efficiency losses are dominated by quiescent current losses, gate drive, transition and core losses. In this case, lower supply voltages yield greater efficiency in that they require less current to drive the MOSFETs and have reduced input power consumption. Efficiency 70 75 80 85 90 95 01 23 45 6 OUTPUT CURRENT (A) VIN = 3.3V VTT = 1.8 Figure 4. Efficiency Curve The region, 1A to 6A, efficiency loss is dominated by MOSFET RDS(ON) and inductor DC losses. Higher input supply voltages will increase the Gate-to-Source voltage on the internal MOSFETs, thereby reducing the internal RDS(ON). This improves efficiency by decreasing DC losses in the device. All but the inductor losses are inherent to the device. In which case, inductor selection becomes increasingly critical in efficiency calculations. As the inductors are reduced in size, the DC resistance (DCR) can become quite significant. The DCR losses can be calculated as follows: LPD = IOUT 2 × DCR |
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