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AD8657ACPZ-R7 数据表(PDF) 18 Page - Analog Devices |
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AD8657ACPZ-R7 数据表(HTML) 18 Page - Analog Devices |
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18 / 24 page ![]() AD8657 Rev. A | Page 18 of 24 V+ V– +IN x R1 D1 D2 M1 M2 M7 M6 M3 M4 M5 VB1 M8 M10 M9 M16 M17 M11 VB2 OUT x M12 M14 M13 M15 I1 R2 –IN x Figure 63. Simplified Schematic RAIL TO RAIL The AD8657 features rail-to-rail input and output with a supply voltage from 2.7 V to 18 V. Figure 64 shows the input and output waveforms of the AD8657 configured as a unity-gain buffer with a supply voltage of ±9 V and a resistive load of 1 MΩ. With an input voltage of ±9 V, the AD8657 allows the output to swing very close to both rails. Additionally, it does not exhibit phase reversal. TIME (200µs/DIV) VSY = ±9V RL = 1MΩ INPUT OUTPUT Figure 64. Rail-to-Rail Input and Output RESISTIVE LOAD The feedback resistor alters the load resistance that an amplifier sees. It is, therefore, important to be aware of the value of feed- back resistors chosen for use with the AD8657. The AD8657 is capable of driving resistive loads down to 100 kΩ. The following two examples, inverting and noninverting configurations, show how the feedback resistor changes the actual load resistance seen at the output of the amplifier. Inverting Configuration Figure 65 shows AD8657 in an inverting configuration with a resistive load, RL, at the output. The actual load seen by the amplifier is the parallel combination of the feedback resistor, R2, and load, RL. Having a feedback resistor of 1 kΩ and a load of 1 MΩ results in an equivalent load resistance of 999 Ω at the output. In this condition, the AD8657 is incapable of driving such a heavy load; therefore, its performance degrades greatly. To avoid loading the output, use a larger feedback resistor, but consider the resistor thermal noise effect on the overall circuit. AD8657 1/2 R1 R2 RL –VSY RL, EFF = RL || R2 +VSY VIN VOUT Figure 65. Inverting Op Amp Noninverting Configuration Figure 66 shows the AD8657 in a noninverting configuration with a resistive load, RL, at the output. The actual load seen by the amplifier is the parallel combination of R1 + R2 and RL. R1 R2 RL –VSY RL, EFF = RL || (R1 + R2) +VSY VIN VOUT AD8657 1/2 Figure 66. Noninverting Op Amp |
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