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AD8033AKS-R2 数据表(PDF) 22 Page - Analog Devices |
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AD8033AKS-R2 数据表(HTML) 22 Page - Analog Devices |
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22 / 25 page ![]() AD8033/AD8034 Rev. D | Page 21 of 24 When selecting components, the common-mode input capacitance must be taken into consideration. Filter cutoff frequencies can be increased beyond 1 MHz using the AD8033/AD8034 but limited open-loop gain and input impedance begin to interfere with the higher Q stages. This can cause early roll-off of the overall response. Additionally, the stop-band attenuation decreases with decreasing open-loop gain. Keeping these limitations in mind, a 2-pole Sallen-Key Butterworth filter with fC = 4 MHz can be constructed that has a relatively low Q of 0.707 while still maintaining 15 dB of attenuation an octave above fC and 35 dB of stop-band attenuation. The filter and response are shown in Figure 60 and Figure 61, respectively. –VS +VS VIN R1 2.49kΩ C3 22pF VOUT AD8033 R2 2.49kΩ R5 49.9Ω C1 10pF Figure 60. 2-Pole Butterworth Active Filter 100M 100k 1M FREQUENCY (Hz) –45 –40 –35 –30 –25 –20 –15 –10 –5 0 5 10M Figure 61. 2-Pole Butterworth Active Filter Response WIDEBAND PHOTODIODE PREAMP Figure 62 shows an I/V converter with an electrical model of a photodiode. The basic transfer function is F F F PHOTO OUT R sC R I V + × = 1 where IPHOTO is the output current of the photodiode, and the parallel combination of RF and CF sets the signal bandwidth. CS RSH = 1011Ω VB IPHOTO RF CF VOUT CM RF CM CD CF + CS Figure 62. Wideband Photodiode Preamp The stable bandwidth attainable with this preamp is a function of RF, the gain bandwidth product of the amplifier, and the total capacitance at the summing junction of the amplifier, including CS and the amplifier input capacitance. RF and the total capacitance produce a pole in the loop transmission of the amplifier that can result in peaking and instability. Adding CF creates a zero in the loop transmission that compensates for the effect of the pole and reduces the signal bandwidth. It can be shown that the signal bandwidth resulting in a 45°phase margin (f(45)) is defined by the expression S F CR C R f f × × π = 2 ) 45 ( where: fCR is the amplifier crossover frequency. RF is the feedback resistor. CS is the total capacitance at the amplifier summing junction (amplifier + photodiode + board parasitics). The value of CF that produces f(45) is CR F S F f R C C × × π = 2 The frequency response in this case shows about 2 dB of peaking and 15% overshoot. Doubling CF and cutting the bandwidth in half results in a flat frequency response, with about 5% transient overshoot. |
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