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AN441 数据表(PDF) 4 Page - STMicroelectronics |
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AN441 数据表(HTML) 4 Page - STMicroelectronics |
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4 / 16 page ![]() Reasons for inrush current in inductive loads AN441 4/16 Doc ID 3579 Rev 3 Figure 3. Magnetic field H versus induction B (continuous rating) According to Equation 2, at start up at zero voltage the current is higher (longer time to integrate voltage and so higher induction reached in the 1st cycle) and so there is a higher risk of reaching magnetic core saturation. Also a second phenomenon can increase risk of saturation. This phenomenon is due to remanent induction. The remanent induction (refer to Br in Figure 3.), corresponds to the point where H equals 0. If a positive voltage is applied from a point where there is a positive remanent induction, the induction will start to increase from a higher initial value, so will reach saturation faster (refer to appendix 1 for further explanation on this phenomenon). To avoid this phenomenon in circuits controlled by an AC switch, device switch on has to be implemented on the reverse polarity according to previous switch off. Figure 4 shows two different test results carried out on a 200 VA 230 V to 12 V transformer. Curve A shows the current waveform, recorded after a previous identical current waveform. The particularity of this waveform is that the first half-cycle conduction is in the same polarity as the previous one. In this case the transformer reaches saturation very rapidly and the transformer behaves like a short circuit. The peak current is limited only by the series resistance of the transformer. Curve B shows the same recording but here with the first half-cycle conduction in reverse polarity compared to the last one. These two curves clearly show that saturation is reached in case A due to previous conduction. Then load current can be approximately eight times higher than if care is taken to always trigger the device for an integer value of full-cycle periods. B t B(t) H Bs Br t i(t) t |
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