| 数据搜索系统,热门电子元器件搜索 |
|
MAX20002CATPC 数据表(PDF) 16 Page - Maxim Integrated Products |
|
|
|||||||||||||||||||||||||||||
MAX20002CATPC 数据表(HTML) 16 Page - Maxim Integrated Products |
|
16 / 19 page ![]() A dominant pole (fdpEA) is set by the compensation capac- itor (CC) and the amplifier output resistance (ROUT_EA). A zero (fZEA) is set by the compensation resistor (RC) and the compensation capacitor (CC). There is an optional pole (fPEA) set by CF and RC to cancel the output capaci- tor ESR zero if it occurs near the crossover frequency (fC, where the loop gain equals 1 (0dB)). Thus: zEA CC 1 f 2C R = π× × pdEA C OUT,EA C 1 f 2 C (R R ) = π× × + pEA F C 1 f 2C R = π× × The loop-gain crossover frequency (fC) should be set below 1/5 of the switching frequency and much higher than the power-modulator pole (fpMOD) SW pMOD C f ff 5 << ≤ The total loop gain as the product of the modulator gain, the feedback voltage divider gain, and the error amplifier gain at fC should be equal to 1. So: FB MOD(fC) EA(fC) OUT V GAIN GAIN 1 V ×× = For the case where fzMOD is greater than fC: EA(fC) m,EA C GAIN g R = × Therefore: FB MOD(fC) m,EA C OUT V GAIN g R 1 V × × ×= Solving for RC: OUT C m,EA FB MOD(fC) V R g V GAIN = ×× Set the error-amplifier compensation zero formed by RC and CC (fzEA) at the fpMOD. Calculate the value of CC a follows: C pMOD C 1 C 2f R = π× × If fzMOD is less than 5 x fC, add a second capacitor (CF) from COMP to GND and set the compensation pole formed by RC and CF (fpEA) at the fzMOD. Calculate the value of CF as follows: F zMOD C 1 C 2f R = π× × As the load current decreases, the modulator pole also decreases; however, the modulator gain increases accordingly and the crossover frequency remains the same. For the case where fzMOD is less than fC: The power-modulator gain at fC is: pMOD MOD(fC) MOD(dc) zMOD f GAIN GAIN f = × The error-amplifier gain at fC is: zMOD EA(fC) m,EA C C f GAIN g R f = ×× Therefore: zMOD FB MOD(fC) m,EA C OUT C f V GAIN g R 1 V f × × ×× = Solving for RC: OUT C C m,EA FB MOD(fC) zMOD Vf R g V GAIN f × = ×× × Set the error-amplifier compensation zero formed by RC and CC at the fpMOD (fzEA = fpMOD). C pMOD C 1 C 2f R = π× × If fzMOD is less than 5 × fC, add a second capacitor CF from COMP to ground. Set fpEA = fzMOD and calculate CF as follows: F zMOD C 1 C 2f R = π× × www.maximintegrated.com Maxim Integrated │ 16 MAX20002/MAX20003 36V, 220kHz to 2.2MHz, 2A/3A Fully Integrated Step-Down Converters with 15μA Operating Current |
|
|
链接网址 |
| ALLDATASHEET是否为您带来帮助? [ DONATE ] |
关于 Alldatasheet | 广告服务 | 联系我们 | 隐私政策 | 数据表链接 | 链接交换 | 制造商名单 All Rights Reserved©Alldatasheet.com |
| Russian : Alldatasheetru.com | Korean : Alldatasheet.co.kr | Spanish : Alldatasheet.es | French : Alldatasheet.fr | Italian : Alldatasheetit.com Portuguese : Alldatasheetpt.com | Polish : Alldatasheet.pl | Vietnamese : Alldatasheet.vn Indian : Alldatasheet.in | Mexican : Alldatasheet.com.mx | British : Alldatasheet.co.uk | New Zealand : Alldatasheet.co.nz |
|
Family Site : ic2ic.com |
icmetro.com |