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ADA4930-2YCPZ-R2 数据表(PDF) 19 Page - Analog Devices |
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ADA4930-2YCPZ-R2 数据表(HTML) 19 Page - Analog Devices |
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19 / 25 page ![]() Data Sheet ADA4930-1/ADA4930-2 Rev. C | Page 19 of 25 MINIMUM RG VALUE Due to the wide bandwidth of the ADA4930-1/ADA4930-2, the value of RG must be greater than or equal to 301 Ω at unity gain to provide sufficient damping in the amplifier front end. In the terminated case, RG includes the Thevenin resistance of the source and load terminations. SETTING THE OUTPUT COMMON-MODE VOLTAGE The VOCM pin of the ADA4930-1/ADA4930-2 is biased at 3/10 of the total supply voltage above −VS with an internal voltage divider. The input impedance of the VOCM pin is 8.4 kΩ. When relying on the internal bias, the output common-mode voltage is within about 100 mV of the expected value. In cases where accurate control of the output common-mode level is required, it is recommended that an external source or resistor divider be used with source resistance less than 100 Ω. The output common-mode offset listed in the Specifications section assumes that the VOCM input is driven by a low impedance voltage source. It is also possible to connect the VOCM input to a common-mode voltage (VCM) output of an ADC. However, care must be taken to ensure that the output has sufficient drive capability. The input impedance of the VOCM pin is approximately 10 kΩ. If multiple ADA4930-1/ADA4930-2 devices share one reference output, it is recommended that a buffer be used. CALCULATING THE INPUT IMPEDANCE FOR AN APPLICATION CIRCUIT The effective input impedance depends on whether the signal source is single-ended or differential. For a balanced differential input signal, as shown in Figure 44, the input impedance (RIN,dm) between the inputs (+DIN and −DIN) is RIN,dm = 2 × RG. +VS ADA4930 +IN –IN RF RF +DIN –DIN VOCM RG RG VOUT, dm Figure 44. ADA4930-1/ADA4930-2 Configured for Balanced (Differential) Inputs For an unbalanced single-ended input signal, as shown in Figure 45, the input impedance is RIN,SE = RG1 ) 1 ( + + β2 β1 β2 β1 where: β1 = F1 G1 G1 R R R + β2 = 2 2 F G2 G R R R + ADA4930 RL VOUT, dm +VS –VS RG1 RG2 RF2 RF1 VOCM RIN, SE Figure 45. ADA4930-1/ADA4930-2 with Unbalanced (Single-Ended) Input For a balanced system where RG1 = RG2 = RG and RF1 = RF2 = RF, the equations simplify to + − = + = = ) 2( 1 F G F G IN,SE F G G R R R R R and R R R β2 β1 The input impedance of the circuit is effectively higher than it would be for a conventional op amp connected as an inverter because a fraction of the differential output voltage appears at the inputs as a common-mode signal, partially bootstrapping the voltage across the input resistor RG1. The common-mode voltage at the amplifier input terminals can be easily determined by noting that the voltage at the inverting input is equal to the noninverting output voltage divided down by the voltage divider formed by RF2 and RG2. This voltage is present at both input terminals due to negative voltage feedback and is in phase with the input signal, thus reducing the effective voltage across RG1, partially bootstrapping it. Terminating a Single-Ended Input This section describes the five steps that properly terminate a single-ended input to the ADA4930-1/ADA4930-2. Assume a system gain of 1, RF1 = RF2 = 301 Ω, an input source with an open- circuit output voltage of 2 V p-p, and a source resistance of 50 Ω. Figure 46 shows this circuit. 1. Calculate the input impedance. β1 = β2 = 301/602 = 0.5 and RIN = 401.333 Ω |
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