ADL5571ACPZ-R7 datasheet(12/16 Pages) AD

12 / 16 page

ADL5571

Rev. 0 | Page 12 of 16

64 QAM OFDMA PERFORMANCE

The ADL5571 shows exceptional performance when used with

a higher order modulation scheme, such as a 64 QAM system.

Figure 22, Figure 23, and Figure 24 illuminate the EVM, gain,

and current consumption performance within the context of a

64 QAM OFDMA system.

POUT (dBm)

1214

1820

2700MHz

2500MHz

2600MHz

Figure 22. EVM vs. POUT Performance at VCC = 3.3 V and

64 QAM OFDMA Signal

FREQUENCY (MHz)

2500 2520 2540 2560 2580 2600 2620 2640 2660 2680 2700

Figure 23. Gain vs. Frequency Performance at VCC = 3.3 V and

64 QAM OFDMA Signal

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

POUT (dBm)

Figure 24. Burst Current vs. POUT at VCC = 3.3 V, 64 QAM,

2350 MHz, 31% 802.16e OFDMA Signal

POWER-ADDED EFFICIENCY

The efficiency of the ADL5571 is defined on the current that it

draws during the data burst of an 802.16e OFDMA signal. In

typical test setup, the average rms current, IAVG, is measured.

However,

IAVG = Duty Cycle (in decimal) × IBURST +

(1 − Duty Cycle [in decimal]) × IDEFAULT

where:

IBURST is the rms current during the data burst of an OFDMA

signal.

IDEFAULT can be the quiescent current drawn when there is no

data burst and the device remains biased, the sleep current

(<1 μA) if the device is defaulted to sleep mode, or the standby

current.

For example, in a 31% duty cycle 802.16e OFDMA signal,

the burst current is calculated by rearranging the previous

equation to get

0.31

)

0.69

(

DEFAULT

AVG

BURST

−

Finally, the PAE is calculated by

100

(mA)

(V)

(mW)

(%)

−

BURST

Power

Input

Power

Output

PAE

When RF is 2.6 GHz, 31% 16 QAM OFDMA signal,

VCC is 3.3 V, RF Output Power is 25 dBm, and RF Input

Power is −4 dBm, the ADL5571 consumes a burst current,

IBURST is 450 mA and PAE = 21%.

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