M41ST87YMX6 datasheet(31/48 Pages) STMICROELECTRONICS

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M41ST87Y, M41ST87W

Clock operation

31/48

adjustment per calibration step in the calibration register. Assuming that the oscillator is

running at exactly 32,768 Hz, each of the 31 increments in the calibration byte would

represent +10.7 or –5.35 seconds per month which corresponds to a total range of +5.5 or

–2.75 minutes per month.

Two methods are available for ascertaining how much calibration a given M41ST87Y/W may

require.

The first involves setting the clock, letting it run for a month and comparing it to a known

accurate reference and recording deviation over a fixed period of time. Calibration values,

including the number of seconds lost or gained in a given period, can be found in application

note AN934, “TIMEKEEPER® calibration.” This allows the designer to give the end user the

ability to calibrate the clock as the environment requires, even if the final product is

packaged in a non-user serviceable enclosure. The designer could provide a simple utility

that accesses the calibration byte.

The second approach is better suited to a manufacturing environment, and involves the use

of the SQW/FT pin. The pin will toggle at 512 Hz, when the stop bit (ST) is '0,' the frequency

test bit (FT) is '1,' and SQWE is '0.'

Any deviation from 512 Hz indicates the degree and direction of oscillator frequency shift at

the test temperature. For example, a reading of 512.010124 Hz would indicate a +20 ppm

oscillator frequency error, requiring a –10 (XX001010) to be loaded into the calibration byte

for correction. Note that setting or changing the calibration byte does not affect the

frequency test output frequency.

If the SQWOD Bit = '1,' the SQW/FT pin is an open drain output which requires a pull-up

resistor to VCC for proper operation. A 500 to10 k resistor is recommended in order to

control the rise time. The FT bit is cleared on power-down.

Figure 21.

Crystal accuracy across temperature

AI07888

–160

10203040506070

Frequency (ppm)

Temperature

°C

–10

–20

–30

–40

–100

–120

–140

–40

–60

–80

–20

= –0.036 ppm/

°C

2 ± 0.006 ppm/°C2

ΔF

= K x (T – T

O = 25°C ± 5°C

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