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LTC2926IGN 数据表(PDF) 20 Page - Linear Technology

部件名 LTC2926IGN
功能描述  MOSFET-Controlled Power Supply Tracker
PDF  28 Pages
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制造商  LINER [Linear Technology]
网页  http://www.linear.com
标志 LINER - Linear Technology

LTC2926IGN 数据表(HTML) 20 Page - Linear Technology

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LTC2926
20
2926fa
Figure 16. Ratiometric Tracking Example
NC
RTB1
24.9k
RTA1
7.68k
2926 F16
LTC2926
S1
FB1
RAMPBUF
TRACK1
TRACK2
GND
PGTMR
VIN
RTB2
18.2k
RTA2
5.36k
FAULT
10k
CPGTMR
1
µF
CMGATE
0.1
µF
MGATE
0.1
µF
VCC
RAMP
VIN
STATUS
STATUS/PGI
ON
ON/OFF
RSGATE
10k
3.3V
VIN
SGATE2
10
Ω
Q2
IRF7413Z
SGATE1
10
Ω
D1
RFB1
15.0k
RFA1
9.53k
S2
FB2
D2
RFB2
15.0k
RFA2
5.76k
FAULT
OUT
IN
SENSE
RX1
100
Ω
1.8V MODULE
3.3V
Q1
IRF7413Z
1.8V
SLAVE1
OUT
IN
SENSE
RX2
100
Ω
2.5V MODULE
3.3V
2.5V
SLAVE2
APPLICATIO S I FOR ATIO
Figure 15. Ratiometric Tracking Waveforms from Figure 16 Circuit
500mV/DIV
SLAVE2
SLAVE1
5ms/DIV
2926 F15
500mV/DIV
5ms/DIV
Ratiometric Tracking Example
This example converts the coincident tracking example to
the ratiometric tracking profile shown in Figure 15, using
two slave supplies and a master ramp signal (not a master
ramp supply). The ramp rate of the master signal remains
unchanged (Step 1), the minimum load resistance of the
slave loads remains unchanged (Step 2), and there is no
delay in ratiometric tracking. Only Step 3 of the three-step
design procedure needs to be considered. In this example,
the ramp rate of the 1.8V slave supply is 60V/s, and the
ramp rate of the 2.5V supply is 83.3V/s. Always verify that
the chosen ramp rate will allow the supplies to ramp-up
completely before RAMPBUF reaches VCC. If the 1.8V slave
supply were to ramp up at 50V/s it would only reach 1.65V
because the RAMPBUF signal would reach its final value
of VCC = 3.3V before the slave supply reached 1.8V.
3. Solve for the tracking resistors that set the desired ramp
rate and voltage offset or time delay of the slave supply.
From Equation 4:
Rk
Vs
Vs
k
TB =•
⎛
⎝⎜
⎞
⎠⎟
=
15 0
100
60
25
.
ΩΩ
Choose RTB = 24.9kΩ.
Since no offset or delay is required, Equation 5c applies:
ΔV = 0V
From Equation 6:
R
V
V
k
V
k
V
k
V
TA =
+−
+
08
08
15 0
08
953
08
24 9
0
.
.
.
.
.
.
.
ΩΩ
Ω 224 9
761
.
.
k
k
Ω
Ω
=
Choose RTA = 7.68kΩ.



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