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MAT02AH 数据表(PDF) 8 Page - Analog Devices

部件名 MAT02AH
功能描述  Low Noise, Matched Dual Monolithic Transistor
PDF  12 Pages
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制造商  AD [Analog Devices]
网页  http://www.analog.com
标志 AD - Analog Devices

MAT02AH 数据表(HTML) 8 Page - Analog Devices

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MAT02
–8–
REV. C
by various offsetting techniques. Protective diodes across each
base-to-emitter junction would normally be needed, but these
diodes are built into the MAT02. External protection diodes are
therefore not needed.
For the circuit shown in Figure 19, the operational amplifiers
make I1 = VX/R1, I2 = VY/R2, I3 = VZ/R3, and IO = VO/RO. The
output voltage for this one-quadrant, log-antilog multiplier/di-
vider is ideally:
VO =
R3RO
R1R2
V XVY
V Z
(VX, VY, VZ > 0)
(4)
If all the resistors (RO, R1, R2, R3) are made equal, then VO =
VXVY/VZ. Resistor values of 50 kΩ to 100 kΩ are recommended
assuming an input range of 0.1 V to +10 V.
ERROR ANALYSIS
The base-to-emitter voltage of the MAT02 in its forward active
operation is:
VBE =
kT
q
In
IC
IS
+ rBEIC, VCB ~ 0
(5)
The first term comes from the idealized intrinsic transistor
equation previously discussed (see equation (1)).
With the oscilloscope ac coupled, the temperature dependent
term becomes a dc offset and the trace represents the deviation
from true log conformity. The bulk resistance can be calculated
from the voltage deviation
∆V
O and the change in collector cur-
rent (9 mA):
rBE =
∆V
O
9 mA
×
1
100
(3)
This procedure finds rBE for Side A. Switching R1 and R2 will
provide the rBE for Side B. Differential rBE is found by making
R1 = R2.
APPLICATIONS: NONLINEAR FUNCTIONS
MULTIPLIER/DIVIDER CIRCUIT
The excellent log conformity of the MAT02 over a very wide
range of collector current makes it ideal for use in log-antilog
circuits. Such nonlinear functions as multiplying, dividing,
squaring, and square-rooting are accurately and easily imple-
mented with a log-antilog circuit using two MAT02 pairs (see
Figure 19). The transistor circuit accepts three input currents
(I1, I2, and I3) and provides an output current IO according to
IO = I1I2/I3. All four currents must be positive in the log-antilog
circuit, but negative input voltages can be easily accommodated
Figure 19. One-Quadrant Multiplier/Divider



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