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A7985ATR 数据表(PDF) 27 Page - STMicroelectronics |
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A7985ATR 数据表(HTML) 27 Page - STMicroelectronics |
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27 / 44 page ![]() DocID023128 Rev 5 27/44 A7985A Application information 44 4. Then calculate C3 in order to place the second pole at four times the system bandwidth (BW): Equation 34 For example, with VOUT = 5 V, VIN = 24 V, IO = 2 A, L = 22 H, COUT = 330 F, and ESR = 70 m the Type II compensation network is: Equation 35 C5 C4 2 R 4 C4 4BW 1 – -------------------------------------------------------------- = R1 1.1k = R2 150 = R4 4.99k = C4 180nF = C5 180pF = |
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