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R7986ATR 数据表(PDF) 20 Page - STMicroelectronics

部件名 R7986ATR
功能描述  3 A step-down switching regulator for aerospace applications
PDF  37 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

R7986ATR 数据表(HTML) 20 Page - STMicroelectronics

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Application information
R7986A
20/37
DocID026997 Rev 1
The transfer function on the LC filter is given by:
Equation 19
where:
Equation 20
Equation 21
As seen in Section 5.3 on page 12, two different kinds of network can compensate the loop.
In the two following paragraphs, the guidelines to select the Type II and Type III
compensation network are illustrated.
6.4.1
Type III compensation network
The methodology to stabilize the loop consists of placing two zeros to compensate the effect
of the LC double pole, therefore increasing phase margin; then to place one pole in the
origin to minimize the DC error on regulated output voltage; finally, to place other poles far
from the zero dB frequency.
If the equivalent series resistance (ESR) of the output capacitor introduces a zero with
a frequency higher than the desired bandwidth (that is: 2
ESR COUT < 1 / BW), the Type
III compensation network is needed. Multi-layer ceramic capacitors (MLCC) have very low
ESR (< 1 m
), with very high frequency zero, so a Type III network is adopted to
compensate the loop.
In Figure 10, the Type III compensation network is shown. This network introduces two
zeros (fZ1, fZ2) and three poles (fP0, fP1, fP2). They are expressed as:
Equation 22
Equation 23
GLC s

1
s
2
 f
zESR
--------------------------
+
1
s
2
 Qf
LC
----------------------------
s
2
 f
LC
-------------------

 2
++
-------------------------------------------------------------------------
=
fLC
1
2
LCOUT
1
ESR
ROUT
---------------
+

------------------------------------------------------------------------
=
fzESR
1
2
 ESR C
OUT

--------------------------------------------
=
Q
ROUT LCOUT ROUT ESR
+


LCOUT ROUT ESR

+
------------------------------------------------------------------------------------------
ROUT
VOUT
IOUT
--------------
=
,
=
fZ1
1
2
 C
3
R1 R3
+


------------------------------------------------
=
fZ2
1
2
 R
4 C4

------------------------------
=
fP0 0
=
fP1
1
2
 R
3 C3

------------------------------
=
fP2
1
2
 R
4
C4 C5
C4 C5
+
--------------------

--------------------------------------------
=




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