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ADP5135ACPZ-R7 数据表(PDF) 21 Page - Analog Devices |
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ADP5135ACPZ-R7 数据表(HTML) 21 Page - Analog Devices |
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21 / 24 page ![]() Data Sheet ADP5135 Rev. 0 | Page 21 of 24 POWER DISSIPATION AND THERMAL CONSIDERATIONS The ADP5135 is a highly efficient micro PMU and, in most cases, the power dissipated in the device is not a concern. However, if the device operates at high ambient temperatures and maximum loading conditions, the junction temperature can reach the maximum allowable operating limit (125°C). When the temperature exceeds 150°C, the ADP5135 turns off all the regulators, allowing the device to cool down. When the die temperature falls below 130°C, the ADP5135 resumes normal operation. This section provides guidelines to calculate the power dissi- pated in the device and to ensure that the ADP5135 operates below the maximum allowable operating junction temperature. The efficiency for each regulator on the ADP5135 is given by 100% IN OUT P P (1) where: η is the efficiency. POUT is the output power. PIN is the input power. Power loss is given by PLOSS = PIN − POUT (2a) or PLOSS = POUT (1− η)/η (2b) Power dissipation can be calculated in several ways. The most intuitive and practical is to measure the power dissipated at the input and all the outputs. Perform the measurements at the worst-case conditions (voltages, currents, and temperature). The difference between input and output power is dissipated in the device and the inductor. Use Equation 3 to derive the power lost in the inductor and, from this, use Equation 7 to calculate the power dissipation in the ADP5135 buck converter. A second method to estimate the power dissipation uses the efficiency curves provided for the buck regulator. When the buck efficiency is known, use Equation 2b to derive the total power lost in the buck regulator and inductor, use Equation 3 to derive the power lost in the inductor, and then calculate the power dissipation in the buck converter using Equation 7. Add the power dissipated in the three bucks to find the total dissipated power. Note that the buck efficiency curves are typical values and may not be provided for all possible combinations of VIN, VOUT, and IOUT. To account for these variations, it is necessary to include a safety margin when calculating the power dissipated in the buck. A third way to estimate the power dissipation is analytical and involves modeling the losses in the buck circuit provided by Equation 8 to Equation 11. BUCK REGULATOR POWER DISSIPATION The inductor losses are external to the device, and they do not have any effect on the die temperature. The inductor losses are estimated (without core losses) by PL ≈ IOUT1(RMS)2 × DCRL (3) where: IOUT1(RMS) is the rms load current of the buck regulator. DCRL is the inductor series resistance. 12 + 1 ) ( r I I OUT1 RMS OUT1 (4) where r is the normalized inductor ripple current. r = VOUT1 × (1 − D)/(IOUT1 × L × fSW) (5) where: L is the inductance. fSW is the switching frequency. D is the duty cycle. D = VOUT1/VIN1 (6) The power loss of the buck regulator is approximated by PLOSS = PDBUCK + PL (7) where: PDBUCK is the power dissipation on one of the ADP5135 buck regulators. PL is the inductor power losses. The ADP5135 buck regulator power dissipation, PDBUCK, includes the power switch conductive losses, the switch losses, and the transition losses of each channel. There are other sources of loss, but these are generally less significant at high output load currents, where the thermal limit of the application is. Equation 8 captures the calculation that must be made to estimate the power dissipation in the buck regulator. PDBUCK = PCOND + PSW + PTRAN (8) The power switch conductive losses are due to the output current, IOUT1, flowing through the P-channel MOSFET and the N-channel MOSFET power switches that have internal resistance, RDSON_P and RDSON_N, respectively. The amount of conductive power loss is found by PCOND = [RDSON_P × D + RDSON_N × (1 − D)] × IOUT1(RMS)2 (9) where RDSON_P is approximately 0.19 Ω, RDSON_N is approxi- mately 0.14 Ω at a 25°C junction temperature, and VIN1 = VIN2 = 3.6 V. At VIN1 = VIN2 = 5.5 V, the values are 0.147 Ω and 0.122 Ω, respectively. |
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