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ADP8860ACPZ-R7 数据表(PDF) 13 Page - Analog Devices |
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ADP8860ACPZ-R7 数据表(HTML) 13 Page - Analog Devices |
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13 / 52 page ![]() ADP8860 Rev. 0 | Page 13 of 52 POWER STAGE Because typical white LEDs require up to 4 V to drive them, some form of boosting is required over the typical variation in battery voltage. The ADP8860 accomplishes this with a high efficiency charge pump capable of producing a maximum IOUT of 240 mA over the entire input voltage range (2.5 V to 5.5 V). Charge pumps use the basic principle that a capacitor stores charge based on the voltage applied to it, as shown in the following equation: Q = C × V (1) By charging the capacitors in different configurations, the charge, and therefore the gain, can be optimized to deliver the voltage required to power the LEDs. Because a fixed charging and discharging combination must be used, only certain multiples of gain are available. The ADP8860 is capable of automatically optimizing the gain (G) from 1×, 1.5×, and 2×. These gains are accomplished with two capacitors (labeled C1 and C2 in Figure 26) and an internal switching network. In G = 1× mode, the switches are configured to pass VIN directly to VOUT. In this mode, several switches are connected in parallel to minimize the resistive drop from input to output. In G = 1.5× and 2× modes, the switches alternatively charge from the battery and discharge into the output. For G = 1.5×, the capacitors are charged from VIN in series and are discharged to VOUT in parallel. For G = 2×, the capacitors are charged from VIN in parallel and are discharged to VOUT in parallel. In certain fault modes, the switches are opened and the output is physically isolated from the input. Automatic Gain Selection Each LED that is driven requires a current source. The voltage on this current source must be greater than a minimum head- room voltage (200 mV typical) to maintain accurate current regulation. The gain is automatically selected based on the minimum voltage (VDx) at all of the current sources. At startup, the device is placed into G = 1× mode and the output charges to VIN. If any VDx level is less than the required headroom (200 mV), the gain is increased to the next step (G = 1.5×). A 100 μs delay is allowed for the output to stabilize prior to the next gain switching decision. If there remains insufficient current sink headroom, then the gain is increased again to 2×. Conversely, to optimize efficiency, it is not desirable for the output voltage to be too high. Therefore, the gain reduces when the headroom voltage is great enough. This point (labeled VDMAX in Figure 27) is internally calculated to ensure that the lower gain still results in ample headroom for all the current sinks. The entire cycle is illustrated in Figure 27. Note that the gain selection criteria apply only to active current sources. If current sources have been deactivated through an I2C command (for example, only five LEDs are used), then the voltages on the deactivated current sources are ignored. |
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